calling a function within a function

Hello all i am currently working on an assignment and I am almost done with it. I'm having a bit of a hard time understanding the calling of a function within a function.

Here is some background to the program. It has generated randomly the phone number, age, credit card number, and has giving each employee a 1 (for secure) or 0 (for unsecured). I bascally have two functions print_secure and print_all. If the information is not secure it will display everything and if it is, it will display certain items.

Here is what I have so far.

Code:

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void CustomerData::print_all()
{
  int empNo;
        cout << "Please enter the Employee Number: ";
        cin >> empNo;
       
        if (0 > empNo || empNo > 49) // checks to make sure that user entered value is within the limit [0 .. 49]
                {
                cout << "The Employee Number entered is out of bound. Please try again.\n";
                return;
                }
       
        //Employee details are printed below
        cout << "\nEmployee details\n";
        cout << "----------------\n";
        cout << "Employee Number: " << employees[empNo].empNo << "\n";
        cout << "Employee Security Preference: " << employees[empNo].security_preference << "\n";
        cout << "Age: " << employees[empNo].empAge << "\n";
        cout << "Phone Number: " << employees[empNo].empphone << "\n";
        cout << "Credit Card Number: " << employees[empNo].empCCNo << "\n";
        cout << "\n\n";
}


/*void CustomerData::print_secure()
{
        //Employee details are printed below
        cout << "\nEmployee details\n";
        cout << "----------------\n";
        cout << "Employee Number: " << employees[empNo].empNo << "\n";
        cout << "Employee Security Preference: " << employees[empNo].security_preference << "\n";
        cout << "Employee Age: " << employees[empNo].empAge << "\n";
        cout << "\n\n";
}*/

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Since I don't want a classmate taking my code I only posted what I think is the main part I need help with.

I was thing of putting an if statement in void CustomerData:: print_all() to reference void CustomerData:: print_secure() but I don't have a clue as how to reference it. Could someone offer some advise?

I don't understand what the question is...

Viggy

Quote:

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Originally Posted by MrViggy

I don't understand what the question is...

Viggy

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He is asking us how he should remove a few cout-lines and call print_secure instead because they actually print the same.

Sorry mate.

I want to create an if statement in the print_all function that says if "security_preference" has a 1 then us the "void CustomerData:: print_secure()" function as the output. How can I go about this?

Quote:

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Originally Posted by Fezzy

Sorry mate.

I want to create an if statement in the print_all function that says if "security_preference" has a 1 then us the "void CustomerData::print_secure()" function as the output. How can I go about this?

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See my last post, and after that you need to create a if to check if you need the print the extra info.

Quote:

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Originally Posted by Fezzy

Sorry mate.

I want to create an if statement in the print_all function that says if "security_preference" has a 1 then us the "void CustomerData:: print_secure()" function as the output. How can I go about this?

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Why cant you think of doing that condition check in the place where you intend to call print_secure() or print_all()?

i mean like,

Code:

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CustomerData cd;
if( security_preference == 1 )
        cd.print_secure();
else
        cd.print_all();

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