compile only one .cpp file???

I'm fairly new to C++, so everything I do is with a single .cpp file. When I used the Bloodshed Dev C++ IDE, I was able to compile and run a single source file. I recently started using Visual C++ 2008 (express edition, if that matters) and now it seems like I can not compile a single file--I have to stick it inside a project in order to compile it. Is there a way around this? With Visual C++ can I compile a single .cpp file without using a "project"?

Any help would be greatly appreciated. Thanks!

It doesn't make any sense IMHO, to compile a single file without any project.

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Originally Posted by VictorN

It doesn't make any sense IMHO, to compile a single file without any project.

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i'm sorry, but you're comment either... he didn't ask whether it makes sense but how to do it, so probalby it makes sense in his case

@jdqie
http://msdn.microsoft.com/en-us/library/ms235639.aspx

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Originally Posted by memeloo

i'm sorry, but you're comment either... he didn't ask whether it makes sense but how to do it, so probalby it makes sense in his case

@jdqie
http://msdn.microsoft.com/en-us/library/ms235639.aspx

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Well, it is interesting info (and, probably, will be useful for OP)! :thumb:

As for me - I don't like using command prompt when I can use VS IDE with all its features as debugging, break points, watch, output and other windows and so on.

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As for me - I don't like using command prompt when I can use VS IDE with all its features as debugging, break points, watch, output and other windows and so on

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++i :thumb:

i = (isEasier == true ? i-1 : i+1)

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Originally Posted by memeloo

i = (isEasier == true ? i-1 : i+1)

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I prefer:

Code:

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if(isEasier)
    ++i;
else
    --i;

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How about:

Code:

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const int increments[] = {1, -1};
i += increments[isEasier];

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Quote:

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Originally Posted by laserlight

How about:

Code:

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const int increments[] = {1, -1};
i += increments[isEasier];

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It won't work for bool isEasier, only for int for which only 0 and 1 are allowed... :cool:
So it would be much more complicated to implement.

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Originally Posted by VictorN

It won't work for bool isEasier, only for int for which only 0 and 1 are allowed...

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There exists an implicit conversion from bool to int whereby false is converted to 0 and true is converted to 1.

Quote:

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Originally Posted by laserlight

There exists an implicit conversion from bool to int whereby false is converted to 0 and true is converted to 1.

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Good to know it!
Thank you! :thumb:

Quote:

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Originally Posted by laserlight

How about:

Code:

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const int increments[] = {1, -1};
i += increments[isEasier];

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nice :lol:

another one:

Code:

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i += 1 * (isEasier * -1);

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Quote:

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Originally Posted by memeloo

another one:

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That won't work: if isEasier is false, the expression evaluates to 0, not -1.

But I realise that my hack has a similiar bug: the array elements should be swapped.

Anyway, we could adapt your example:

Code:

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i += isEasier * -2 + 1;

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Quote:

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Originally Posted by laserlight

That won't work: if isEasier is false, the expression evaluates to 0, not -1.

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****! :confused::mad::D how could i not see it :\

i += !isEasier - isEasier;


Probably the best one to make people scratch their heads twice figuring out what this does.