"cout <<" Problem???

<code>
Object M
string computer;
getline(cin, computer);
cout << "Input Accepted...";
if (computer == "") {
cout << "Initializing List Mode...\n";
M.run();
} else {
M.do(computer);
}
</code>
When I run my code it will do "do" or "run" and print out "Input Accepted" afterwards. I'm not understanding why?? Thanks for any help.

O and completely guessed on how to mark code so hope that's right.

use [] around the code word.

Try this:

Code:

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cout << "Initializing List Mode..." << std::endl;

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This will flush the stream cout and print immediately what you streamed to it so far. If you do not flush the stream, its content will get buffered and printed later, which in your case may be at the end of your application.

Quote:

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Originally Posted by TommyFeticini

O and completely guessed on how to mark code so hope that's right.

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no worries you can edit your post using the edit button on that post. the correct tags are [CODE]code here[/CODE]

Code:

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code here

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