creating a string array to hold user inputed thing

Help with the below code. It will not put anything in the arraY?!

string locations[100];
cin >> regionName;
locations[0]=regionName;

while( regionName != STOP)
{
int i = 1;
cout<<end1 << "input" << regionName;
locations[i] = regionName;
cin >> regionName;
int++;
}

Much longer program but i'm having trouble just getting stuff into the array to work with it. my teacher gave us a txt input so it is working and outputting all the regionNames. But when I check to see if anything is inside array above number 2 it doesn't work. And the last regionName enter is always in array part number 1. array spot 0 works... :\ ?

any help would be great

Dear Rich child
I guess being rich would definitely make one smart and it is true
as I see you making this question

1. you might need learn to about getline to eliminate priblems of space char within each regionname if any
2. it is 'i' that is to increase not 'int' and should be put infront of whilelloop too
3. from 2 you don't have to initialise location[0], hah
4. learn also about vector, you can make a vector of strings instead of string arrays


-Hoang Thach Quan

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Dear Rich child

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Who ?

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learn also about vector, you can make a vector of strings instead of string arrays

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Please stop throwing with the phrase 'vector'... instead of that... answer the question. Vectors are nothing more than a simple list, and they are very OVERRATED.

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But when I check to see if anything is inside array above number 2 it doesn't work.

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You keep setting 'i' to 1.

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int i = 1;

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Define 'i' outside the loop.

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int i = 1;
while( regionName != STOP)
{
  ....
  i++;
}

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Originally Posted by Skizmo

Vectors are nothing more than a simple list

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Well, std::list is nothing more than a simple list. std::vector is nothing more than an extremely convenient wrapper around a dynamic array. Big different in data structure land! (I know what you meant.)

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, and they are very OVERRATED.

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Perhaps, but they beat the heck out of doing the same operations manually. Of course, in some cases "the same operations" are not necessary.