question about two dimensional arrays

Hi to all,
Hope you all will be fine.I am confused about Arrays . Consider this, it's a single dimensional integer array

Code:

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int product_codes[3] = {10, 972, 45};

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Also character array

Code:

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char name[] = {'S', 'a', 'm', '\0'};

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See, For initialize single dimensional array we use one set of curly({ }) braces and separate each character with comma(,).

But what about this

Code:

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char Ones[10][10] = {"One", "Two","Three","Four","Five","Six","Seven","Eight","Nine"};

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See, in this we also use singe set of curly braces and separate each character with comma(,), but it's not a single dimension, it's a two dimensional array. How and why?

If we declare it like this i get an error

Code:

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char Ones[10] = {"One", "Two","Three","Four","Five","Six","Seven","Eight","Nine"}; //Error

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Can someone please explain to me why we declare it with two dimension and why i getting error while creating it with single dimension.

It's a two dimension array

Code:

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int matrix[2][4] ={ {1, 2, 3, 4}, {10, 20, 30, 40} };

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We used two set of curly braces inside a single set of curly braces to initialize two dimensional array but we didn't initialize {"One", "Two",....} array in this manner why?

Thanks

Quote:

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char Ones[10][10] = {"One", "Two", ...

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'O' 'n' 'e' '/0' == 4 * char
'T' 'w' 'o' '/0' == 4 * char

Each comma is separating an array of characters.

Quote:

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char name[] = {'S', 'a', 'm', '\0'};

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could be written as

Code:

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char name[]  = "Sam" ;
char name[10] = "Sam" ;

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Hi,
Thanks. You mean the code

Code:

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char Ones[10][10] = {"One", "Two","Three","Four","Five","Six","Seven","Eight","Nine"};

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is equivalent to

Code:

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char Ones[10][10] ={{'O', 'n', 'e', '\0'}, {'T', 'w', 'o', '/0'}, {'T', 'h', 'r', 'e', 'e', \0'}, .....};

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Means each string("One", "Two",...) is itself a separate character array separated by commas as i did above.

Thanks

Effectively yes, a string literal is a special form of char array.

The primary difference between the {'a', '\0'} notation and the "a" notation is that while the former may only be used in initialization, the latter may be used anywhere:

Code:

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char str[] = {'a', '\0'};
strcpy(str, "b");

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Also, it is not necessary to copy string literals into a variable; you can simple point at their location in (probably read-only) memory instead. But better make sure you do so in a const manner or you risk ugly problems:

Code:

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const int *i = {1,2,3}; // NOT possible
int i2[] = {1,2,3}; // just fine, the array is copied to the stack
const char *s = "Hello"; // just fine, so long as s is a const char*
char *s2 = "World"; // the compiler will accept this, but it's a bad idea because attempting to modify the string literal "in-place" without copying it to the stack will likely crash your program
char s3[] = "Test"; // just fine, the literal is copied to the stack

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