help me in this code ..

hi all,

Suppose myList points to a list with the elements 34 65 27 89 12 (in this order). The statement
myList.splitMid(sublist);
splits myList into two sublists: myList points to the list with the elements 34 65 27, and sublist points to the sublist with elements 89 12.

i receive an error in linkedList.h

please help !! the file in attachment

Hi,

in your attachement there are 2 headers and one source file. Since that is not a compileable project, what do you expect us to do?

Isn't it possible to tell us the error? Post the code (in code tags) and tell us the error you got.

I do not have the time to build a project out of your files...

With regards
Programartist

sorry for that

the error is her (((((( secondList = first;)))))

void linkedListType<Type>::splitAt(linkedListType &secondList,
const Type& item)
{
//void splitAt(List <Type> &seclist, const Type &item){
nodeType<Type> * first;
nodeType<Type> * link;
nodeType<Type> *pNode = first ;
bool found = false;

if (isEmptyList())
cout<< "The List is empty\n";
else
for (pNode = first; pNode != NULL; pNode = pNode->link)
if (item == pNode->info){
first = pNode;

secondList = first;
found = true;
}
if (found = false){cout<<"Item not found";}
}

#endif

Code and other tags...

Code:

---

nodeType<Type> * first;
nodeType<Type> *pNode = first ;

---

Always initialize your variables.

Code:

---

nodeType<Type> * first = NULL;
nodeType<Type> *pNode = first ;

---

Now you can see, 'first' is nothing, so 'pNode' also is nothing.

Code:

---

secondList = first;

---

'secondList' is a refference, not a pointer. Also, it is of a different type.