handle character at string(c)

hi,
i wanted to know if there is any way to read character`s from string one by one,
and set it in other string.
i mean
i have this string:

char *get = "hello";

now i want to get over the string char by char and if the letter != 'l' copy it to other string, like :

Code:

---

char *copy;
char c; int i;
for (i=0;get[i] != '\0';i++)
c = get[i];
if (c != 'l')
{
  copy[j] = get[i];
    j++;
}

---

i dont want to do it by strchr,strtok... i want do it by reading char by char from the string,
(the all problem when i tring to add the char to the copy array it tells me :
canot covert char to char *
any idea?
Thanks,
Or.

Is the code you posted really the code you got that error message for? I don't see what statement in that code could trigger that error.

I do see several problems in that short snippet though:

• You would need to allocate memory to hold the output characters and assign its address to copy. Since you don't know in advance how many characters will be skipped I would suggest to allocate strlen(get)+1 chars.
• You are missing a pair of braces. The way it is the for loop would only comprise the single statement following the for line.
• You are neither declaring nor initializing j.
• You don't copy the '\0' terminator at the end of the string.

This pseudo-code is the sort of thing that would do the job. It should explain to you a method.

Code:

---

// Get length of source char array (using strlen).
// Make target char array of this size (plus one for the terminating zero) using new.

int positionInTargetArray = 0;
for (int i=0;i==lengthOfSourceCharArray;++i) // For each character in the source char array and the terminating zero....
{
  if (sourceCharArray[i] != 'l') // Check if it should be copied...
  {
    targetArray[positionInTargetArray]=sourceCharArray[i];  // Copy it to the next available slot
                                                            //  in the target array
    ++positionInTargetArray; // Move the target array next slot counter along one.
  }
}

// Be sure that you don't miss the terminating zero at the end of the char arrays.

---

I don't know what would cause that error, but you'll need to allocate memory for copy.

Code:

---

string get = "somethingblue";
string copy;
for (unsigned i = 0; i < get.size(); ++i)
    if (get[i] != 'l')
        copy += get[i];

---