Display an image in Gui

I got the image path from the file directory using the dlgOpen.GetPathName() function and it is saved to a char array eg path.I need to display it on Gui ,better on a new Dialog box.This image may be bmp or jpg.

Help required

You can use OleLoadPicture() look at this sample from MSDN: How to load graphics files and display them in Visual C++

Cheers

for bmp you dont need any coding. just draw a picture control on your dialog from resource editor in vc++ and add a bmp, you are done.

for jpg you need to use some functions such as OleLoadPicturePath() ie using some COM api. If you want I can provide you some code snippet

Sample code is helpful

bmp load should be easiest one to display image on dialog. anyways the way to load jpg is here.

Code:

---

        IPicture *m_pic = NULL;
        RECT rc;
        CDC *pdc = NULL;
        long hmWidth;
        long hmHeight;
       
        ::OleLoadPicturePath(L"your_jpg_file", NULL, 0, 0, IID_IPicture, reinterpret_cast<void **>(&m_pic));

        m_pic->get_Width(&hmWidth);
        m_pic->get_Height(&hmHeight);

        pdc = m_jpg.GetDC();
        m_gif.GetClientRect(&rc);

        m_pic->Render(pdc->m_hDC, rc.left, rc.top, rc.right - rc.left, rc.bottom - rc.top,
                                0, hmHeight, hmWidth, -hmHeight, &rc);
        m_pic->Release();

        m_gif.ReleaseDC(pdc);

---

m_jpg is the static picture control in which the image is being drawn.

Thanks

But how change the height and width of the static control according to image height and width.For example 200 * 200 image ,the display also 200 * 200.for 64 * 64,the image also looks 64 *64.Now the problem is that the width and height on the dialog is same