Designin The Game Of Go Muko Using Arrays??

Exercise 8.5: The game of Go Moku (also known as Pente or Five Stones) is similar to Tic-Tac-Toe, except that it played on a much larger board and the object is to get five squares in a row rather than three. Players take turns placing pieces on a board. A piece can be placed in any empty square. The first player to get five pieces in a row -- horizontally, vertically, or diagonally -- wins. If all squares are filled before either player wins, then the game is a draw. Write an applet that lets two players play Go Moku against each other.

Your applet will be simpler than the Checkers applet from Section 8.5. Play alternates strictly between the two players, and there is no need to hilite the legal moves. You will only need two classes, a short applet class to set up the applet and a Board class to draw the board and do all the work of the game. Nevertheless, you will probably want to look at the source code for the checkers applet, Checkers.java, for ideas about the general outline of the program.

The hardest part of the program is checking whether the move that a player makes is a winning move. To do this, you have to look in each of the four possible directions from the square where the user has placed a piece. You have to count how many pieces that player has in a row in that direction. If the number is five or more in any direction, then that player wins. As a hint, here is part of the code from my applet. This code counts the number of pieces that the user has in a row in a specified direction. The direction is specified by two integers, dirX and dirY. The values of these variables are 0, 1, or -1, and at least one of them is non-zero. For example, to look in the horizontal direction, dirX is 1 and dirY is 0.

int ct = 1; // Number of pieces in a row belonging to the player.

int r, c; // A row and column to be examined.

r = row + dirX; // Look at square in specified direction.
c = col + dirY;
while ( r >= 0 && r < 13 && c >= 0 && c < 13
&& board[r][c] == player ) {
// Square is on the board, and it
// contains one of the players's pieces.
ct++;
r += dirX; // Go on to next square in this direction.
c += dirY;
}

r = row - dirX; // Now, look in the opposite direction.
c = col - dirY;
while ( r >= 0 && r < 13 && c >= 0 && c < 13
&& board[r][c] == player ) {
ct++;
r -= dirX; // Go on to next square in this direction.
c -= dirY;
}

the solution is --> http://www.java2s.clanteam.com/c8/ex-8-5-answer.html

Here is my applet. It uses a 13-by-13 board. You can do the same or use a normal 8-by-8 checkerboard.