Question about char pointer arrays

I have a question regarding to char pointer arrays.

char* S="Just a try!";
char* Array[5];
Array[0]=S;
cout << Array[0];


This code prints the text "Just a try!".Does Array[0] point to the first character J's address in memory or point to the character J?If Array[0] points to the first character J's address in memory,then why don't we use *(Array[0]) instead of just writing Array[0]?When we type cout << Array[0] why doesn't it write the address of Array[0]?

I am a bit confused about pointers like you see.

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Originally Posted by AwArEnEsS

Does Array[0] point to the first character J's address in memory or point to the character J?

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Since, naturally, the character 'J' resides at its own address in memory, both sides of your "or" are true, IOW it doesn't matter because essentially it means the same.

Quote:

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If Array[0] points to the first character J's address in memory,then why don't we use *(Array[0]) instead of just writing Array[0]?When we type cout << Array[0] why doesn't it write the address of Array[0]?

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There's a subtle difference between the two: While Array[0] represents (a pointer to) an array of characters, *(Array[0]) represents a single, isolated character, namely the first one in that array.

What cout << actually does output, though, solely depends on the the operator<<() implementations that take a right-hand operand of type char * or char, respectively. It would be absolutely no problem to implement the operator taking a char * so that it just outputs the first character in the array pointed to, just like the char variety does, it's just that the stahdard mandates otherwise.

HTH

Array[0] points the address of the first character of the string .

Thanks for your answers.

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Originally Posted by bluecoder

Array[0] points the address of the first character of the string .

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Array[0] is the first character of the string. It doesn't point to anything, address or otherwise. Array points to to the first character, Array[0] is the first character.

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Originally Posted by GCDEF

Array[0] is the first character of the string. [...]

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:D Actually, I was on the verge of succumbing to the temptation of replying essentially the same to bluecoder's post. However, the OP's Array is declared as:

Code:

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char* Array[5];

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;) :p :rolleyes:

Quote:

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Originally Posted by Eri523

:D Actually, I was on the verge of succumbing to the temptation of replying essentially the same to bluecoder's post. However, the OP's Array is declared as:

Code:

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char* Array[5];

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;) :p :rolleyes:

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Thanks for the correction.