Help using a character as parameter

I have a multiple choice function below that is part of a larger program but I am having trouble having it operate with characters as inputs and arguments. It has to be a character input, but I kinda want it to act like an integer, how do i do that?

Code:

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void addition(int *Preward) //function that is called by the users selection
{
 
 
    int random1, random2;
    int order;
    int one, two, three;
    int rando1, rando2;
    char a, b, c;                              // ERROR
    char userselect;                        //ERRRORR
    srand(time(NULL)); //generates fresh numbers each time.
    random1 = 1+(rand()%99); // from 1-99
    random2 = 1+(rand()%99); // from 1-99
    rando1 = 2+(rand()%198); // 2 to 198
    rando2 = 2+(rand()%198); // 2 to 198
    order = 1+(rand()%3);
 
 
    switch(order){
        case 1: printf("\n%d + %d = ", random1, random2);
            one = (random1+random2);
            two = (rando1);
            three = (rando2);
            printf("\n select from the following\n a) %d b) %d  c) %d\n", one, two, three);
            scanf("%c", &userselect);                        //ERROR
                if (userselect == a){                          //ERROR
                    printf("Congratulations\n\n");
                    *Preward = 1;
                }
                else{
                    printf("incorrect, correct answer is a\n\n");
                }break;

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Code:

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if (userselect == a)

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Where do you initialize "a" in your code? I don't see it.

Code:

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    char a, b, c;                              // ERROR

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Why are these errors? You're declaring variables, so what's the problem? The only problem I see is that you didn't initialize them.

Regards,

Paul McKenzie

You actually don't need the three chars: a, b, and c.
I'm not completely familiar with c coding, but with c++ you would..
char charVariable;
cin >> charVariable;
if(charVariable == 'a');

You need 'a', 'b', or 'c'. If you do a without the apostraphes then it computes the actual ascii value of a.
So, by saying:
if(charVariable == a)
You're actually saying:
if(charVariable == 97)

Code:

---

void addition(int *Preward) //function that is called by the users selection
{
 
 
    int random1, random2;
    int order;
    int one, two, three;
    int rando1, rando2;
    char userselect;                        //ERRRORR
    srand(time(NULL)); //generates fresh numbers each time.
    random1 = 1+(rand()%99); // from 1-99
    random2 = 1+(rand()%99); // from 1-99
    rando1 = 2+(rand()%198); // 2 to 198
    rando2 = 2+(rand()%198); // 2 to 198
    order = 1+(rand()%3);
 
 
    switch(order){
        case 1: printf("\n%d + %d = ", random1, random2);
            one = (random1+random2);
            two = (rando1);
            three = (rando2);
            printf("\n select from the following\n a) %d b) %d  c) %d\n", one, two, three);
            scanf("%c", &userselect);                        //ERROR
                if (userselect == 'a'){                          //ERROR
                    printf("Congratulations\n\n");
                    *Preward = 1;
                }
                else{
                    printf("incorrect, correct answer is a\n\n");
                }break;

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