Statement concerning queue's?

Isn't this statement invalid:

queueADT<int> newQueue;

shouldn't it be:

queueType<int> newQueue;

*note: ADT stands for Abstract Data Type

I don't think that putting ADT would be proper and also wrong where Type should be instead?
Does anyone know what I am talking about, or correct me? Thanks.

Eh, it depends on the type name. Both queueADT and queueType are valid identifiers, so either can be used to name the queue container type. If you really wanted to, you could name it Wh1t3gh0st and write:

Code:

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Wh1t3gh0st<int> newQueue;

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except that it would be a pretty bad type name here.

ok thanks similar question what if i were to put any number within a parenthesis and taken into account that the number can be a double or int whatever. is this valid:

queueADT<double> newQueue(-24)

or like you said following the same pattern

"whatevername"<data type> "functionname"(integer, number, etc.)

correct?

like if I were to do something like:

queueType<double> queue(-20);

then

queue.addQueue(10);

would this mean that there is initially a value of -20 in the queue? then 10 -20 would be in the queue roughly saying?

Just want to know what the it is actually doing if there is a value in that first line of code:

queueType<double> queue(-20);

thanks

You need to refer to the relevant documentation.

Quote:

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Originally Posted by Wh1t3gh0st

like if I were to do something like:

queueType<double> queue(-20);

then

queue.addQueue(10);

would this mean that there is initially a value of -20 in the queue? then 10 -20 would be in the queue roughly saying?

Just want to know what the it is actually doing if there is a value in that first line of code:

queueType<double> queue(-20);

thanks

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As laserlight said, you'll need to look up the documentation for queueType/queueADT. If they have a constructor which takes a parameter then queue(-20) may be valid. If they don't, it isn't. The documentation will tell you what constructors there are.