Could someone know how this code work?

we need to make a pseudo code of this code :(


#include <stdio.h>

int main()
{
int n,r[10],i;
printf("Enter a number to get its hexadecimal equivalent\n");
scanf("%d",&n);
for(i=0; n!=0; i++)
{
r[i]=n%16;
n=n/16;
}
i--;

for(; i>=0; i--)
{
if(r[i]==10) printf("A");
else if(r[i]==11) printf("B");
else if(r[i]==12) printf("C");
else if(r[i]==13) printf("D");
else if(r[i]==14) printf("E");
else if(r[i]==15) printf("F");
else printf("%d",r[i]);
}
printf("\n");
}

The key is in the operators % and /. The first one is modules operator and the second one is division.

When you do n%16, the number is divided by 16 and reminder is stored in your array of capacity 10. Then you move to next by dividing it 16 and storing it in n. N will become zero and you will come out of the first loop leaving all base 16 number system in your array.

Next you enter one more loop and print the array content by replacing 10-15 with hexadecimal value. Enough :)