How to write an array into 3 diff. arrays? odd, even, negative

question : Place the even lucky numbers in an array called evenList, the odd lucky numbers in an array called oddList, and the negative lucky numbers in an array called negList.

//So in main main i passed the array as parameter and the size;

void lucknumberlist(int favnum[], int size)
{
int even = 0, odd = 0, neg = 0;
int evenArray[even];
int oddArray[odd];
int negArray[neg];

if(favnum[even] % 2 == 0)
{
evenArray[even] = favnum[even];
even++ ;
}
else if(favnum[odd] % 2 == 1)
{
oddArray[odd] = favnum[odd];
odd++;
}
else
{
negArray[neg] = favnum[neg];
neg++;
}

//tried printing to check if worked.. but no luck!!

for (int i = 0; i < size; i++)
{
cout << oddArray[i] << " ";
}
}

Code:

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int even = 0, odd = 0, neg = 0;
int evenArray[even];

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In standard c++, this is not a valid way to define an array as even is a variable and not a const. Even if this way of defining an array was legal, you would have an array of 0 elements as even is 0.

You would be better off using vectors to store the even, odd and negative numbers.

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