LDPC:How to declare

Hi,
I am working LDPC encoding and decoding.In Vivado HLS, I need to transform a parity-check matrix H (that only consists of ones and zeros) from a non-standard to a standard form through C/C++ programming language.

Its showing wrong result while generating codeword, please debug my program.

Code:

---

int main()
{
    // coding for the general form beginning using rows and cols
    int i,j,msg_length,sum=0,k;
  int message[]={1,1,0}          //single dimensional array
    int rows=3,cols=6,r=0,r2,c;
    int Generator[10][10],code[10][10]={0};
    int temp[10][10]={0};
    int H_Matrix[3][6]={{1,1,0,0,1,0},{1,0,0,1,0,1},{1,1,1,0,0,1}}; //2-dimensional array
*/
....................
...............
*/

for(i=0;i<rows;i++)
{
    for(j=0;j<cols;j++)
    {
        Generator[i][j]=H_Matrix[i][j];
    //    printf("%d\t ",Generator[i][j]);
    }
    printf("\n");
}

for (i = 0; i < 1; i++) {
      for (j = 0; j < cols; j++) {
        for (k = 0; k < rows; k++) {
          sum = sum^( message[i][k]&Generator[k][j]); //How to compute? This line showing error while compiling
        }
 
        code[i][j] = sum;
        sum = 0;
      }
    }
 
//code wrd
printf("the code word \n"); 
for(i=0;i<1;i++)
{
    for(j=0;j<cols;j++)
    {
        printf("%d\t ",code[i][j]);
    }
    printf("\n");
} 

}

---

message[i][k] results an error because message is a one-dimensional array. You probably meant to write:

Code:

---

sum = sum ^ (message[k] & Generator[k][j]);

---

By the way, it looks like you have the same code as the original poster over here: How to multiply single dimensional array with 2-dimensional array, except that you've provided much more context from the get go. Hope you're actually the same person or working on the same project together and not some plagiarism involved... but then if so it is good to pick one forum and stick to it, or if you wish to switch help channel, inform the previous one.