Doctor Luz, I've found them:
321000
42101000
521001000
The next one is the 10 digits self-describing number that I posted a while ago.
Now, does nobody know the answer to my question?. It's easy, I can assure you... :) :p :D
Ana.
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Doctor Luz, I've found them:
321000
42101000
521001000
The next one is the 10 digits self-describing number that I posted a while ago.
Now, does nobody know the answer to my question?. It's easy, I can assure you... :) :p :D
Ana.
ooh did the barman guess by the man's uniform
They ARE correct!Quote:
Originally posted by Simon666
Are those really correct? I think it depends where you start from:
0
10
1110
3110
132110
1113122110 10 digits
311311222110
1
11
21
1211
111221
312211
132221
11133211
31231221
13111213112211
111331121113212221
31232112311312113211
Your example has nothing to do with the initial question. The question was about a number self explanatory. In your example, it is a series, and therefore requires the beginning of the series.
A few things altogether:
- Codeguru is starting to go veeeery slowly again, I don't know if I'll be able to post much more from now on.
- Simon, I think you didn't understand what a self-describing number is, in the number you posted there are lot of 1's and their number don't coincide with the second digit.
- SeventhStar, YOU GOT IT!!!. Yes, it was the uniform the man was wearing. So it's your turn.
Ana. :)
yep CodeGuru is getting slow again verrrrrrrrrrrrrrry slllllllllllllllow;
so Score:
1. Saturno, Gabriel and Simon - 3pts
2. Elrond, John, solarflare, and me - 2pts
Asker: me
question:
you have twelve balls and a pair of scales. All balls are equal in size but one of them is different from the others in weight (you don't know if it's lighter or heavier). With 3(three) measurements with the scales determine which this ball is. I need a 100% secure way. with Maximut three measurements.
answers should be like pseudo code:
i put X balls. if these are heavier do this etc...
15 minutes to post a reply!!!!!Quote:
Originally posted by saturno7
Doctor Luz, I've found them:
321000
42101000
521001000
The next one is the 10 digits self-describing number that I posted a while ago.
Now, does nobody know the answer to my question?. It's easy, I can assure you... :) :p :D
Ana.
321000 NO
42101000 YES
521001000 YES
To Simon: Elrond is right, that's a serie of auto explanatory numbers. Maybe the problem is my bad english.
Oh ****, didn't read the task correct again. I was still thinking of this thread from a while ago.
Put 5 and 5 balls (1 measure)
From those whose weight is more put 2 and 2 (2 measures)
if the weight is the same the different ball is the other (finish)
if not compare the 2 balls wich had more weight before. (3 measures)
Oh, the first one was a typing mistake. I was trying to say 3211000. Is this one right? :)Quote:
Originally posted by Doctor Luz
15 minutes to post a reply!!!!!
321000 NO
42101000 YES
521001000 YES
To Simon: Elrond is right, that's a serie of auto explanatory numbers. Maybe the problem is my bad english.
Now where did I see that one before?Quote:
Originally posted by SeventhStar
Asker: me
question:
you have twelve balls and a pair of scales. All balls are equal in size but one of them is different from the others in weight (you don't know if it's lighter or heavier). With 3(three) measurements with the scales determine which this ball is. I need a 100% secure way. with Maximut three measurements.
answers should be like pseudo code:
i put X balls. if these are heavier do this etc...
Quote:
Originally posted by saturno7
Oh, the first one was a typing mistake. I was trying to say 3211000. Is this one right? :)
YES!
:D ;)
We alredy had such thread early and even had such task, but only about coins. :)
I think, that Simon remember about it ;)
Nevertheless U can have even 27 balls by this way.
9, 9, 9
3, 3, 3
1, 1, 1
There were elso enough more difficult task about coins there.
I don't know if the answer is right, but Doctor Luz has already answered in this thread, a few posts ago. Doesn't this mean that he gets a point and it's his turn? :)
Ana.
I did not read carefully, they are 12 not 10
then 6-6
From the 6 with more weight 2-2, if they have the same weight 1-1 from the other two, else 1-1 frome those which weight is bigger.
read the question CAREFULLY here it is again:
you have twelve balls and a pair of scales. All balls are equal in size but one of them is different from the others in weight (you don't know if it's lighter or heavier). With 3(three) measurements with the scales determine which this ball is. I need a 100% secure way. with Maximut three measurements.