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Doctor Luz, your answers are not correct because you DON'T know if the "false" ball is heavier or lighter!
If you start working on the heavy load and if the "false" ball is lighter, you won't find it!
The result being that I still don't have a 100% working solution :(
Wow! Such a long time without an answer!
Will I get a point?...
:D :D :D :D
Ohh, yeh, I was not so carefully!
But nevertheless, We already discass it somewhere in October.
Something like this: We have 3 parts,
a - 4(a1,a2,a3,a4),
b - 4(b1,b2,b3,b4),
c - 4(c1,c2,c3,c4)
Then weight a and b.
1) = , so we have part c (4 balls), and it is not big problem to find what :)
2) <(or >) , for ex. a < b
This means that if the false ball in a - it weight some less, if in b - some havier.
then we have else 3 parts:
1(a1, a2, b1) 2(a3, a4, b2 ) and (b3, b4, c1 ) ( c1 - is a good ball )
weight 1 and 2.
if (1 == 2) then false ball in 3 and it is heavier (b1 or b2)
for ex.1 < 2 (or 1> 2 it is not the reason)
so we have 3 balls only - (a1, a2, b2),
b1, a3, a4 - are good, because othervise we have 2 > 1 ( remember that b - is heavier, a - lighter ).
so we have (a1, a2, b2)
then weight a1 and a2
if == , than b2 - false and it is heavier
a1<a2 we have a1 , because a - lighter
So, that is right solution :)
somehow it misses when ball is b1(heavier) i thinkQuote:
Originally posted by dimm_coder
Ohh, yeh, I was not so carefully!
But nevertheless, We already discass it somewhere in October.
Something like this: We have 3 parts,
a - 4(a1,a2,a3,a4),
b - 4(b1,b2,b3,b4),
c - 4(c1,c2,c3,c4)
Then weight a and b.
1) = , so we have part c (4 balls), and it is not big problem to find what :)
2) <(or >) , for ex. a < b
This means that if the false ball in a - it weight some less, if in b - some havier.
then we have else 3 parts:
1(a1, a2, b1) 2(a3, a4, b2 ) and (b3, b4, c1 ) ( c1 - is a good ball )
weight 1 and 2.
if (1 == 2) then false ball in 3 and it is heavier (b1 or b2)
for ex.1 < 2 (or 1> 2 it is not the reason)
so we have 3 balls only - (a1, a2, b2),
b1, a3, a4 - are good, because othervise we have 2 > 1 ( remember that b - is heavier, a - lighter ).
so we have (a1, a2, b2)
then weight a1 and a2
if == , than b2 - false and it is heavier
a1<a2 we have a1 , because a - lighter
So, that is right solution :)
I'm looking more carefully once more but you look too.
nope my mistake! :rolleyes:
youre right!
you win a point and get to ask a question!
Sorry my I've read it wrong :) ;)
Score
1. Saturno, Gabriel and Simon - 3pts
2. Elrond, John, solarflare, and me - 2pts
3. dimm_coder - 1pt
Asker: dimm_coder
(a1, a2, b1) < (a3, a4, b2 )Quote:
Originally posted by SeventhStar
somehow it misses when ball is b1(heavier) i think
I'm looking more carefully once more but you look too.
I this case b1 cannot be heavier, because we will have (a1, a2, b1) > (a3, a4, b2 ), but we have
(a1, a2, b1) < (a3, a4, b2 )
_______________________________
Ok, but if siriously, as I've mentioned above, I solved this task in October, when we had analog thread, now I've only remembereded it :)
So, don't know can I have point or no ;)
I can give my right to ask question for someone who has interesting question now :)
Because some interesting tasks I knew, I posted already there, and I think that, at least, Simon, Gabrial, Irona, Elrond can know solution for them
:)
If YOU had solved it before, have a point now...
another question.
Two freinds that haven't met since highschool meet accidently on the street. They havent seen or heard eachother from years. Here's a part of their conversation:
'How's life?'
'fine! Thank you! Do you know I have a daoughter?'
'no! What's her name?'
'like her mother's'
'Oh! And how old is the little Jenny?'
How did the friend know the daughter's name?
The friend is not a real friend and is messing around with the other guy's wife? :eek: :D ;) :pQuote:
Originally posted by SeventhStar
Two freinds that haven't met since highschool meet accidently on the street. They havent seen or heard eachother from years. Here's a part of their conversation:
'How's life?'
'fine! Thank you! Do you know I have a daoughter?'
'no! What's her name?'
'like her mother's'
'Oh! And how old is the little Jenny?'
How did the friend know the daughter's name?
sorry but NO :pQuote:
Originally posted by Simon666
The friend is not a real friend and is messing around with the other guy's wife? :eek: :D ;) :p
that way they would've at least heard of each other.
I got it! One is the two friends is a woman called Jenny... They aren't two men, maybe two women or maybe man and woman. :D :D
What the metter :confused:
He is simply know his wife from school?
May be he was married from school when they see each other every day, and for this reason his friend know about his wife
this IS the right answer:Quote:
Originally posted by saturno7
I got it! One is the two friends is a woman called Jenny... They aren't two men, maybe two women or maybe man and woman. :D :D
so you win a point and are next...
1. Saturno - 4 pts
2. Gabriel and Simon - 3pts
3. Elrond, John, solarflare, and me - 2pts
4. dimm_coder - 1pt
I think that is the answer he wants but actually it could be anything. I do not appreciate such questions. :rolleyes:Quote:
Originally posted by saturno7
I got it! One is the two friends is a woman called Jenny... They aren't two men, maybe two women or maybe man and woman. :D :D
:D
My question:
There's some blood in the ceiling of your bedroom. Why?
Ana. :p :)
I've squished a muskito (i dont know how to spell this)