arrays

the code you have there won't even compile, once you fix this you might find that you've already done what you wanted. The setw hangs up the compiler, it's not a part of the iostream library in that form, though I don't know how to use it. I can help your recoding problem somewhat.

notice how this: void display_array (......); is different than these:
int display_array(.....);
float display_array(.....);
double display_array(.....);
char display_array(.....);

you treat void differently than the others inside the {} brackets. Typing void in front of the identifier means that it dose NOT return a value. This also means you do not need to place the "return;" statement at the end of your function. Otherwise you will need to return a char, int, float or double.

Secondly cout can be uses multiple times after it has been called. You've done this allready

here: cout << "\nOffset: " << setw(2) << i;

so telling it to type a little more by placeing the spaces between <<'s.

Well, I've not run that code, but it seems to run off the end of the screen as it is. the computer would automaticly place words on the next line down once this happened or it might just type over the last ones. you need to insert an <<endl at the end of so many cout statements to properly get it to go down a line. To do this you'll need to have an if statment in the for loop that says someing like this:
if (i% NumberOfEntriesWantedOn_A_Line==0 && i!=0)
{
cout<<endl;
}

that way it will only activate the number of entries wanted. The % sign means that if you devide
10 by 8 (written like this in code: 10\8 ) the computer can give you two answers the nomal one is 1 because 10 is divided into 8 one time. the second answer the computer could give you is the remainder of the numbers once divided. so 10-8 is two, therefore, the "modulus" of 10/8 is 2. the % returns the two and is an agruement. Note that the if statement I wrote has an agruement asking if the remainder is zero. and if i itself is not a zero (because 0/anyghing is 0.)

As to the "Best" way to get your task done, well, there are lots of ways to do most everything in programing. Thats part of why I like it. You get to design it how you want. Hope that helps.

Quote:

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Originally Posted by ehoi

Well, I've not run that code, but it seems to run off the end of the screen as it is. the computer would automaticly place words on the next line down once this happened or it might just type over the last ones. you need to insert an <<endl at the end of so many cout statements to properly get it to go down a line. To do this you'll need to have an if statment in the for loop that says someing like this:
if (i% NumberOfEntriesWantedOn_A_Line==0 && i!=0)
{
cout<<endl;
}

that way it will only activate the number of entries wanted. The % sign means that if you devide
10 by 8 (written like this in code: 10\8 ) the computer can give you two answers the nomal one is 1 because 10 is divided into 8 one time. the second answer the computer could give you is the remainder of the numbers once divided. so 10-8 is two, therefore, the "modulus" of 10/8 is 2. the % returns the two and is an agruement. Note that the if statement I wrote has an agruement asking if the remainder is zero. and if i itself is not a zero (because 0/anyghing is 0.)

As to the "Best" way to get your task done, well, there are lots of ways to do most everything in programing. Thats part of why I like it. You get to design it how you want. Hope that helps.

---

// Headers and Other Technical Items

#include <iostream>
using namespace std;

// Function Prototypes

void pause(void);

// Variables

int iq[8] = {80,90,100,110,120,130,140,150};
double money[6] = {1.21,1.31,1.41,1.51,1.61,1.75};

int x; // Used as a flag to control for loops

//******************************************************
// main
//******************************************************

int main(void)
{
cout << "\nThe oiginal IQ's:" << endl;
for(x = 0; x < 5; x++)
{
cout << iq[x] << endl;
}

cout << "\n\nThe second person became smarter, what is his new IQ -->: ";
cin >> iq[1];

cout << "\n\nThe revised IQ:" << endl;
for(x = 0; x < 5; x++)
{
cout << iq[x] << endl;
}

pause();

cout << "\n\nThe money for 6 members:" << endl;
for(x = 0; x < sizeof money / sizeof money[0]; x++)
{
cout << money[x] << endl;
}

pause();
return 0;
}

//******************************************************
// pause
//******************************************************

void pause(void)
{
cout << "\n\n";
system("PAUSE");
cout << "\n\n";
return;
}

//******************************************************
// End of Program
//******************************************************

Whn you post code, please use code tags. Go advanced, select the code and click '#'.

Quote:

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Originally Posted by Zaccheus@Work

Not to mention holding financial information in floats!

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would be just very slightly less worse had it been doubles :p

some people seem to be smart enough to see floats won't be good enough, but run into the pitfall thinking that doubles don't have the same inate problems as floats do.

Quote:

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Originally Posted by 2kaud

Whn you post code, please use code tags. Go advanced, select the code and click '#'.

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Probably even more important, when you bump threads, try to make sure they're not five years old.

Will do, thanks for the advice.