Printing patterns

Quote:

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Originally Posted by ttrz

Code:

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printf("%c        %c\n", '*', '*');

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While this will work, substituting literals is really not necessary here:

Code:

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printf("*        *\n");

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will do the same thing.

Quote:

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Originally Posted by adam86107

The instructor referred to it as a C++ class anyway.

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Well, to be blunt, there are a lot of instructors who claim to be teaching C++, who are actually teaching "C with a few bits of C++ syntax thrown in". That isn't the way professional programmers write C++, but it is unfortunately very common in schools. The reason for this is that C makes it easier to teach the underlying data structures and algorithms than proper C++, because proper C++ does a lot of the low-level stuff for you. It's important to learn those low-level ideas, but you should also become familiar with the "right" way of doing things, because it's both easier and safer.

OK, so here is what I've tried to do and apparently I am way off base. Everything I've tried keeps getting implicit declarations of the functions in main, but without modifying main I cant seem to figure out how to get rid of this. Here is my latest failure:

int main (void) {
print_1_9();
print_2_7();
print_3_5();
print_4_3();
print_5_1();
print_6_0();
print_5_1();
print_4_3();
print_3_5();
print_2_7();
print_1_9();
return 0;
}
int myfunction (void) {
print_1_9;
printf("* *\n");
print_2_7();
printf("** **\n");
print_3_5;
printf("*** ***\n");
print_4_3;
printf("**** ****\n");
print_5_1;
printf("***** *****\n");
print_6_0;
printf("************\n");
return 0;
}

Any extra help is much appreciated as this program is due today.

I've changed it up some but still to no avail. Here's the newest:

int main (void) {
print_1_9();
print_2_7();
print_3_5();
print_4_3();
print_5_1();
print_6_0();
print_5_1();
print_4_3();
print_3_5();
print_2_7();
print_1_9();
return 0;
}
int myfunction (void) {
int print_1_9();
printf("* *\n");
return 0;
}
int myfunction1 (void) {
int print_2_7();
printf("** **\n");
return 0;
}
int myfunction2 (void) {
int print_3_5();
printf("*** ***\n");
return 0;
}
int myfunction3 (void) {
int print_4_3();
printf("**** ****\n");
return 0;
}
int myfunction4 (void) {
int print_5_1();
printf("***** *****\n");
return 0;
}
int myfunction5 (void) {
int print_6_0();
printf("************\n");
return 0;
}

Name your functions print_1_9, print_2_7, print_3_5, print_4_3, etc. Don't name them myFunction - that is just something I used when giving you an example.

To keep it simple, implement the functions first, before main. See if this helps you.

Code:

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#include <iostream>

void print_1_9() {
printf("*        *\n");
}

int main (void) {
print_1_9();
return 0;
}

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If you can't figure out how to make it work from this example, I think you are in trouble and should read the first few chapters of your C or C++ programming book again.