union

Quote:

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Originally Posted by ninja9578

I didn't say that the example I posted was that case, I was just saying that it's a more advanced case, that might be undefined.

What would happen here?

Code:

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union foo {
  bool b;
  short s;
  int i;
};

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Is it defined where the bits for each are stored, or is that up to the compiler?

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I believe that's compile dependent. I think...

Viggy

As I read this http://www.open-std.org/jtc1/sc22/wg...2011/n3242.pdf (page 226, §5) each member in a union should have the same address so the mapping is defined. Endian has to be considered though.

That's right, each member in the union starts at the same address.

Viggy