Light the first torch by the 2 ends, and the second by one end. When the first torch is finished (after 1/2 hour), light the second end of the second torch.
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Light the first torch by the 2 ends, and the second by one end. When the first torch is finished (after 1/2 hour), light the second end of the second torch.
Fine. So now it's Elrond's turn.
Ummm,,, but they worked. Is there another flaw in this question?? Can't we just forget it, and you tell us the answer!Quote:
Originally posted by SeventhStar
Nope thats not what these operators do.
I'd ask a question now, but I pledged not to :(.
sorry guys yesterday my pc went crazy and i could post so:
so you know what the base numbers are
operators:
i and m mean plus but more correctly
barwoniganalhul = 199 = 1 after the 6th 33
babumbarwonhul = 37 = 4 after the first 33
o and s mean -22+ but more correctly:
babusgutarhul = 48 = 4 after the first 11 from the second 33
t and y mean - 44 +
babutfarokhul = 59 = 4 after the first eleven before the third 33
a and an operator that wasnt given mean before
gautaragutarhul = 64 = 2 before the second 33
so it's not that solarflare isn't correct but he didn't get the idea of the whole thing
Elrond doesn't seem to show up. Anyone else a question?
Well, there's one I have heard of a few years ago and liked it very much. It might be widely known by now, however, I could give it a try.
OK, I'll go ahead:
Four people need to cross a narrow bridge at night.
The bridge will only hold a maximum of two people. A torch must be carried by someone crossing the bridge - else they will fall down. But there is only one torch, it's battery life is limited to 1 hour.
One person takes 25 minutes to cross, another 20 minutes, another 10 minutes and another 5 minutes.
When two people cross the bridge together, they must go at the speed of the slowest.
You have to get all four people across in 1 hour. Throwing the torch back or similar tricks are not allowed.
Sorry for not showing up earlier. :o
The guy of 10 and the guy of 5 cross (10 minutes passed)
The guy of 10 goes back (20 minutes passed)
The guy of 25 and the guy of 20 cross (45 minutes passed)
The guy of 5 goes back (50 minutes passed)
the guy of 10 and the guy of 5 cross (60 minutes passed)
And by the way, I still don't have any question, so fell free to ask.
1. Gabriel 8
2 me and Simon 6 (go Simon only 660 to go :D)
3. Elrond 5
4. Saturno 4
5. solarflare 3
6. John 2
7. dimm_coder, Xplorer, galathaea, doctor luz, gstercken 1
Question:
Two meteorites going in the same direction passed one point simultaneously. The first one was going with a speed of 200km per hour. The second one passed 1km the first hour, 2 the second and N km in the N th hour. Within how many days will the second meteorite reach the first one?
After 399 hours. Time needed so
1+2+3+...+N = N*200
yep 399 is correct
Two persons, Mr S. et Mr P. , repectively know the sun and the product of two integers A and B. A and B are between 2 and 100.
They don't know A and B.
S. et P. meet and start talking :
P. : "I can't find these numbers"
S. : "I knew it"
P. : "Then I have know what they are !"
S. : "Really ?! Then I have know as well !"
What are the values of A and B ?
They are the solution of a second degree ecuation
X*X-(A+B)*X+(A*B)=0
s know the sum and p know the product right?Quote:
Originally posted by Elrond
Two persons, Mr S. et Mr P. , repectively know the sun and the product of two integers A and B. A and B are between 2 and 100.
They don't know A and B.
S. et P. meet and start talking :
P. : "I can't find these numbers"
S. : "I knew it"
P. : "Then I have know what they are !"
S. : "Really ?! Then I have know as well !"
What are the values of A and B ?
I was wondering about this too... But then I noticed that the names 'S' and 'P' were probably not chosen at random... ;)