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I need help with something, probably simple...
I want to have an "If (something AND something) then....."
but when I try using && I get errors...
Here's what I tried (basically)
Thanks for any help.Code:if (GetAsyncKeyState(VK_F8) && x > 1) {
action... }
My crystalball broke down last week... ordered a new one, but I'm still waiting for it. So, while I'm waiting for my new crystalball, maybe you could tell us which errors you get, because right now, I can't read your mind.
Lol, well I figured that someone would be able to give an example of what the if statement would look like...Quote:
Originally Posted by Skizmo
I'm getting errors for different things because of how I wrote the code out, kind'a badly, but either way, could you give a small example of using an if statement with the "&&" and I can use that to make my own. I don't want someone to do it for me, like tell me what code I need, I'm trying to learn how to do everything by myself so I wont need a lot of help in the future...
Thanks.
is this supposed to be:Quote:
if (GetAsyncKeyState(VK_F8) && x > 1)
if ( (GetAsyncKeyState(VK_F8) && x ) > 1)
or
if (GetAsyncKeyState(VK_F8) && (x > 1) )
Compiler probably doesn't know? You have two evaluations there.
Thanks to you, I got it... I needed an extra pair of () around it...Quote:
Originally Posted by KingTermite
Here's what worked.
[code]if ((GetAsyncKeyState(VK_F8)) && z > 1)]/code]
Thanks for helping.
Other than you changed x to z, there's no reason adding the extra parenthesis would have any effect on compilation or execution. They're superfluous in that case. Something else changed as well.
Idk, I'm using Visual C++ Express 2008 and that's all I had to change for it to work. And I just copied and pasted that time, because the variable in there was z, I just used x when I typed it here. Anyways, I don't know why if that ain't the reason, but I did it in 10 different spots, and having the extra () around it got rid of all the errors.Quote:
Originally Posted by GCDEF
I agree. I don't understand why they would have made a difference where you put them.Quote:
Originally Posted by GCDEF
Maybe it's because I have so many if's inside one another? Not sure, but it says I don't have an if for an else if I don't have the extra (). Either way, as long as it works lol.Quote:
Originally Posted by KingTermite
Not knowing "why" it works is almost as bad as it not working, IMO.Quote:
Originally Posted by Tesujin
Yeah but it seems like it makes sense to me... i mean..Quote:
Originally Posted by KingTermite
((getkey(vkf8)) && (z > 1))
1. beginning of whole thing
2. beginning of getasynckey
3. beginning of key
4. close key
5. close getasynckey
6. open z>1
7. close z>1
8. close whole thing
thats what it seemed like to me... sorry if im wrong..
May be while you were adding those unneeded parenthesis, you accidentally fixed some mismatched ones?Quote:
Originally Posted by Tesujin
But if that was the case, I would have gotten errors before adding the extra &&'s to the if statement. Also, I added opening and closing parenthesis, so wouldn't the unmatched ones still be there?Quote:
Originally Posted by VladimirF
I know you think that fixed it, but it didn't. Those extra parenthesis don't do anything in this case. There was something else.Quote:
Originally Posted by Tesujin
This statement in post #11
is not the same as this one in post #5Code:((getkey(vkf8)) && (z > 1))
I'm guessing you went with the former?Code:if((GetAsyncKeyState(VK_F8)) && z > 1)
Would this ever be true? I think (a && b) returns either 0 or 1, never >1.Quote:
Originally Posted by KingTermite
That wouldn't be ambiguous to the compiler.Quote:
Originally Posted by KingTermite
Neither one is ambiguous to compiler. For the programmer – may be.Quote:
Originally Posted by GCDEF
Compare operators have higher precedence than logical AND.
I thought a && b returns true or false. i'm not sure that true is equivalent to 1Quote:
Originally Posted by w3rd
That is true in C++.Quote:
Originally Posted by Amleto
true is converted to 1.Quote:
Originally Posted by Amleto