Undefinded problem...

Hello,

I have the following JavaScript:

Code:

---

var ev_index = "001";

if (ev_index == "001")
  {
  return "hello";
  }

---

if the var ev_index does not = to 001 I want it to exit and not do anything.

at the minute it returns undefinded.

Does anyone know how to just exit the if statement without returning anything.

Thanks.

Only functions can return a value. You are looking for break.

Hello,

I have now done the following:

Code:

---

var ev_index = "001";

if (ev_index == "001")
{
        return "hello";
}
else
{
        break;
}

---

If the ev_index = 001 it works fine

but, If the ev_index = any other number it comes up with a Syntax error. (invalid break statement)

Am I using the break correct ?

Aaron.

No. It is not correct. As I said in my previous post, you cannot use return in a in if() statement. Only functions have returns. Hence why you are getting an undefined return.

But, why even bother checking the positive if you only want to check for a negative? Save yourself some code.

Code:

---

if (ev_index != "001") {
        // do processing here
}

---