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Type: Posts; User: nuzzle
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Well, it looks like you're right. VS2012 actually outputs 2.
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I have a feeling it's defined in C++ 11. At least that's how I interpret section 5.2.6 in the standard: "The value computation of the ++ expression is sequenced before the modification of the operand...
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As I indicated, the recursive function can be simplified and then it becomes even clearer how it works,
void ReadListBackward(node* p) {
if (!p) {
printf("T!\n"); // recursion terminates
...
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I made a net search and found this link I think applies to your problem,
http://www.computational-logistics.org/orlib/topic/TSPPD%20with%20LIFO%20Loading/Paper/TSPPDL.pdf
But the...
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It works because of recursion (a function calls itself repeatedly until a termination criterion is met).
Here the ReadListBackward function is calling itself and each time advancing along the...
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Or you could make two roundtrips to all locations. During the first roundtrip you push all items on the LIFO as you find them. Afterwards you pop all items and immediately push them back on again in...
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Thank you, I get it now.
I think you've come up with a nice solution strategy. First sorting the bridges according to "from" and then finding the longest increasing subsequence among the "to"....
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Well, you should never give up type information you then have to recover using downcasting at runtime.
Since objects know what type they are you can always ask them for their type. It's what my...
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One can always argue what should or shouldn't be in a top class. But the fact remains, this design strategy is very common in major OO designs such as Qt and integral to many languages such as Java...
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Dr. Dobb's has a recent list of C++ 11 books,
http://www.drdobbs.com/cpp/c-reading-list/240155654
In addition to this I would recommend C++ Coding Standards by Sutter and Alexandrescu, a best...
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Using a top base class is quite common in OO designs actually. In both Java and C# it's even built into the language. The best known C++ example is maybe Qt where every class inherits a common top...
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Well, if you get it please explain why bridging the third and fourth pairs is the correct solution?
2 5 8 10
6 4 1 2
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Downcasting (including sidecasting as in this case) is bad OO and should preferably be avoided because it's not typesafe.
In my suggestion it's established by design (and not just a known fact)...
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Why can't you have just one bridge? That bridge would connect all cities above the river with all cities below.
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You don't want to let MyInterface inherit MyBaseclass but maybe you could let MyInterface define a method which returns a pointer to MyBaseclass? Essentially that method just returns this.
With...
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A thrown exception is not a return point.
Multiple return points increases code complexity. Therefore they're error prone and should be avoided (although I sometimes use them myself in idiomatic...
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Reference counting smart pointers can be considered GC light, and std::shared_ptr is the standard C++ way of accomplishing "self-deleting" objects.
Reference counting has one major drawback though...
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That would be bad programming in its own right.
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Yes, you can do that. I would use a friend function with parameters by const reference. Const reference is the preferred passing mode if you don't intend to change the parameters.
What I suggested...
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Here,
void hashT<elemType>::insert(int hashIndex, const elemType& rec)
elemType (which is a StateData) is passed by const reference, whereas here
// friend bool operator!=(StateData &,...
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And Microsoft always do their utmost to satisfy people's desire to complain. This time they really outdid themselves. Turning desktops into handheld devices was a stroke of genius. What other move...
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A good rule of thumb is to make each class represent a single concept. So I suggest you limit Planet to represent one celestial body only, and introduce a new SolarSystem class to represent many...
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I think your best bet is to contact the author actually. If you show a keen interest in someone's work they're often very willing to discuss it with you.
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Well if you have an O(N^2) algorithm already you've come quite far. :)
To me it looks like your problem is equivalent to the Weighted Interval Scheduling Problem. To see that you only have to view...
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Of course there exists an algorithm. This for example,
1. Generate all possible subsets of the N "permutations". There are 2^N such subsets.
2. From all possible subsets select the valid (no...
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