basic string

[hillxy]

I have a basic string "phraseinList", I want to know how many words are there in this string, the words are seperated by ' ' or '-'

For example:
string phraseinList = "Fronto-parietal lobe";

Note: '-' only appears in some of the strings.

I want the result "3". I know I can do that by countint ' ' and '-', but is there any simple way to do that?

Thanks.

[mwilliamson]

std::string s = "test test test";
int count = 0;
std::string::size_type pos = 0;

while( (pos = s.find( pos, " -" ) ) != std::string::npos )
++count;

[tmecham]

And to think, I would have done something lengthy like this:

std::string str = "test- word count-test -";
int word_count = 0;
std::string cur_word;
for(int i = 0; i < str.length(); ++i)
{
char c = str[i];
if( c == ' ' || c == '-')
{
if(cur_word.length() > 0)
{
cur_word = "";
++word_count;
}
}
else
cur_word += c;
}
if(cur_word.length() > 0)
++word_count;

[AvDav]

int how_many_words(const char *str, const char *delims)
{
	if(!str || !delims || !*delims || !*str) return -1;

	unsigned words=0, i;
	bool in_word=false, is_delim=false;
	
	do
	{
		for(i=0; delims[i]; ++i)
			if((is_delim = delims[i]==*str))
			{
				in_word = false;
				break;
			}
		if(!is_delim && !in_word)
		{
			++words; 
			in_word=true;
		}
	}
	while(*++str);

	return words;
}
int main()
{
	int num = how_many_words("red, green,    blue --- are colors.", ", -.");
	return 0;
}

[Philip Nicoletti]

Another one ...

#include <iostream>
#include <string>

int count_words(const std::string& input, const std::string& delims)
{
    int count = 0;

    std::string::size_type beg_index , end_index;

    beg_index = input.find_first_not_of(delims);

    while (beg_index != std::string::npos)
    {
       end_index = input.find_first_of(delims,beg_index);
       //std::cout << input.substr(beg_index,end_index-beg_index) << std::endl; // the word
       beg_index = input.find_first_not_of(delims,end_index); // get ready for next search
       ++count;
    }

    return count;
}

int main()
{
    std::string s = "yes-another word counter";

    std::cout << count_words(s," -") << std::endl;

    return 0;
}

[Shehzad_Salim]

Originally posted by Philip Nicoletti
Another one ...

#include <iostream>
#include <string>

int count_words(const std::string& input, const std::string& delims)
{
    int count = 0;

    std::string::size_type beg_index , end_index;

    beg_index = input.find_first_not_of(delims);

    while (beg_index != std::string::npos)
    {
       end_index = input.find_first_of(delims,beg_index);
       //std::cout << input.substr(beg_index,end_index-beg_index) << std::endl; // the word
       beg_index = input.find_first_not_of(delims,end_index); // get ready for next search
       ++count;
    }

    return count;
}

int main()
{
    std::string s = "yes-another word counter";

    std::cout << count_words(s," -") << std::endl;

    return 0;
}

excellent