About Process Time

[BlueFish]

I tried a nested looping and found a weird question. I hope some expert can help me solve it. Here is my code

#include <iostream>  
#include <ctime>  
  
using namespace std;  
  
int main()  
{  
        for(int i=0; i<50000; i++)  
        {  
                int a[] = {0,0,0,0,0,0,0,0,0,0};  
                int b[] = {0,0,0,0,0,0,0,0,0,0};  
  
                for(int j=0; j<10; j++)  
                {  
                        b[j] = int(10 * rand() / (RAND_MAX + 1));  
                        a[b[j]]++;                  
                }  
        }  
  
        cout << "Time spend: " << clock() << "\n";  
  
        system("pause");  
        return 0;  
}

#include <iostream>  
#include <ctime>  
  
using namespace std;  
  
int main()  
{  
        for(int i=0; i<50000; i++)  
        {  
                int a[] = {0,0,0,0,0,0,0,0,0,0};  
                int b[] = {0,0,0,0,0,0,0,0,0,0};  
  
                for(int j=0; j<10; j++)  
                        b[j] = int(10 * rand() / (RAND_MAX + 1));  
  
                for(int j=0; j<10; j++)  
                        a[b[j]]++;  
        }  
  
        cout << "Time spend: " << clock() << "\n";  
  
        system("pause");  
        return 0;  
}

After these processes the time spend show me twice for loop will faster than single process. I'm very confuse of this process

[olivthill]

Sorry, I'm confused about your sentence: "After these processes the time spend show me twice for loop will faster than single process."I have no idea what you meant, but I would bet two GM shares that the second program is faster, because loops are not very time consuming when they contain a short line instead of a big paragraph.