This is a c program that is failing to compile. The error occurs in the calcLabs() function. The error called out is (btw, I'm using VS 2010): Error 4 error C2143: syntax error : missing ';' before 'type'

I don't understand why the compiler is not letting me declare variables in the calcLabs() function!

Code:
#include<stdio.h>
#include<stdlib.h>

void calcPercent(double *);
double calcLabs();
double calcExams();
double calcFinal();
char calcLetter(float);

main()
{
	
	char fullname[16];
	double perGrade = 100;
	char letGrade = 'A';
	int scount = 0;
	FILE * fptr;
	fptr = fopen("grades.txt", "w");
	if(fptr == NULL)
	{
		//message exit
	}
	fprintf(fptr, " GRADES REPORT\n\n" );
	fprintf(fptr, " NAME              %%GRADE          LETTER\n" );

	printf("\n Enter a student or 0 to exit: ");
	scanf("%15[^\n]s", fullname);
	fflush(stdin);
	while(fullname[0]!='0')
	{
		printf("\n Processing ...");
		calcPercent(&perGrade);
        //calcLetter();
		fprintf(fptr, "\n %-16s%9.2f%4c ", fullname, perGrade, letGrade);
		scount++;
		printf("\n Enter a student or 0 to exit: ");
	    scanf("%15[^\n]s", fullname);
		fflush(stdin);
	}
	fprintf(fptr, "\n\n Student count is %d ", scount);
	fclose(fptr);
	
	return(0);

}

void calcPercent(double * ptr_perGrade)
{
	double labTotal;
	double examTotal;
	double finalTotal;
	labTotal = calcLabs();
	examTotal = calcExams();
	finalTotal = calcFinal();
	//*ptr_perGrade = labTotal+examTotal+finalTotal;
}

double calcLabs(void)
{
	printf("Got here calcLabs");
	double score = 0.0; // THIS IS THE LINE CALLED OUT IN THE ERROR
/**	double sum = 0.0;
	double average = 0.0;
	double result = 0.0;
	for(int i = 0; i < 8; i++)
	{
		printf("\n Enter Lab: ");
		scanf("%f", &score);
		sum += score;
	}
	average = sum / 8;
	result = average * .4;
**/
	return 0.0;
}

double calcExams()
{
	printf("Got here calcExams");
	return 0.0;
}

double calcFinal()
{
	printf("Got here calcFinal");
	return 0.0;
}

char calcLetter()
{
	printf("Got here calcLetter");
	return 'a';
}