-
April 25th, 2014, 08:07 AM
#1
Finding the string of number present inside brakects after a keywrod in a file
I am reading a file whick looks like following:
Code:
10 = NAND(1, 3)
11 = NAND(3, 6, 5)
15 = NAND(9, 6, 2, 8)
Problem: I have to find the word "NAND" and then find the numbers inside the brackets because they are the inputs to that NAND gate. I have written a code below but that code can detect the fixed number of inputs. I need a code which can detect any number of inputs (whether 2 inputs or more than two). But i don't understand how do i do that?
My code:
Code:
string input_str ("INPUT"), output_str ("OUTPUT"), nand_str("NAND");
while (getline( input_file, line ))
{
std::size_t guard_found = line.find(guard_str);
if (guard_found ==std::string::npos)
{
///NAND
std::size_t found_2 = line.find(nand_str);
if (found_2!=std::string::npos)
{
vector <string> nand_inputs;
found_2 = line.find_first_of('(', found_2 + 1);
//find first input
string first_input = line.substr( found_2 + 1, ( line.find_first_of(',', found_2) - found_2 - 1) );
nand_inputs.push_back(first_input);
//Second input
found_2 = line.find_first_of(',', found_2 + 2);
string second_input = line.substr( found_2 + 2, ( line.find_first_of(')', found_2) - found_2 - 2) ); //CHANGED "found_2 + 1" TO "found_2 + 2" AND "found_2 - 1" TO "found_2 - 2"
nand_inputs.push_back(second_input);
cout<<"first: "<<first_input;
}
}
}
-
April 25th, 2014, 08:49 AM
#2
Re: Finding the string of number present inside brakects after a keywrod in a file
This code snippet should give you help with the way forward,
Code:
const string nand_str = "NAND(";
const string nline = "15 = NAND(9, 6, 2, 8, 10, 23)";
size_t nand,
del;
if ((nand = nline.find(nand_str)) != string::npos)
nand += nand_str.length();
for (; nand != string::npos; nand = del)
if ((del = nline.find_first_of(",)", nand)) != string::npos)
cout << atoi((nline.substr(nand, del++ - nand)).c_str()) << endl;
PS Why are you saving the nand inputs as a vector<string>? Why not save them as a vector<int>?
ie
Code:
vector<int> nand_inputs;
....
nand_inputs.push_back(atoi((nline.substr(nand, del++ - nand)).c_str()));
Last edited by 2kaud; April 25th, 2014 at 09:05 AM.
All advice is offered in good faith only. All my code is tested (unless stated explicitly otherwise) with the latest version of Microsoft Visual Studio (using the supported features of the latest standard) and is offered as examples only - not as production quality. I cannot offer advice regarding any other c/c++ compiler/IDE or incompatibilities with VS. You are ultimately responsible for the effects of your programs and the integrity of the machines they run on. Anything I post, code snippets, advice, etc is licensed as Public Domain https://creativecommons.org/publicdomain/zero/1.0/ and can be used without reference or acknowledgement. Also note that I only provide advice and guidance via the forums - and not via private messages!
C++23 Compiler: Microsoft VS2022 (17.6.5)
-
April 25th, 2014, 09:15 AM
#3
Re: Finding the string of number present inside brakects after a keywrod in a file
Thanks alot. It did work for me BUT it is printing an extra space i.e. " " for the inputs which are between 1st and last input. For example, the inputs which i am getting for Second line of my text file are "3", " 6", " 5". See, there is an extra space before 6 and 5 which should not be present. I can try to remove this space by making an "if condition" and getting an another string. But is there any good and short solution for it?
PS: I am not converting the string into number because my i have to process the input names as string only in my further code.
-
April 25th, 2014, 09:28 AM
#4
Re: Finding the string of number present inside brakects after a keywrod in a file
BUT it is printing an extra space i.e. " " for the inputs which are between 1st and last input
Coverting to a number doesn't have this issue I'll have a look and get back.
All advice is offered in good faith only. All my code is tested (unless stated explicitly otherwise) with the latest version of Microsoft Visual Studio (using the supported features of the latest standard) and is offered as examples only - not as production quality. I cannot offer advice regarding any other c/c++ compiler/IDE or incompatibilities with VS. You are ultimately responsible for the effects of your programs and the integrity of the machines they run on. Anything I post, code snippets, advice, etc is licensed as Public Domain https://creativecommons.org/publicdomain/zero/1.0/ and can be used without reference or acknowledgement. Also note that I only provide advice and guidance via the forums - and not via private messages!
C++23 Compiler: Microsoft VS2022 (17.6.5)
-
April 25th, 2014, 09:31 AM
#5
Re: Finding the string of number present inside brakects after a keywrod in a file
Thank you. But i need it into string format only
-
April 25th, 2014, 09:42 AM
#6
Re: Finding the string of number present inside brakects after a keywrod in a file
Assuming there is only one space after the , then possibly the simplest way is
Code:
const string nand_str = "NAND(";
const string nline = "15 = NAND(9, 6, 2, 8, 10, 23)";
size_t nand,
del;
if ((nand = nline.find(nand_str)) != string::npos)
nand += nand_str.length() - 1;
for (; nand != string::npos; nand = del)
if ((del = nline.find_first_of(",)", nand)) != string::npos)
cout << nline.substr(nand + 1, del++ - nand - 1) << endl;
Note that if there are more than 1 space after the , then this simple solution won't work.
All advice is offered in good faith only. All my code is tested (unless stated explicitly otherwise) with the latest version of Microsoft Visual Studio (using the supported features of the latest standard) and is offered as examples only - not as production quality. I cannot offer advice regarding any other c/c++ compiler/IDE or incompatibilities with VS. You are ultimately responsible for the effects of your programs and the integrity of the machines they run on. Anything I post, code snippets, advice, etc is licensed as Public Domain https://creativecommons.org/publicdomain/zero/1.0/ and can be used without reference or acknowledgement. Also note that I only provide advice and guidance via the forums - and not via private messages!
C++23 Compiler: Microsoft VS2022 (17.6.5)
-
April 25th, 2014, 09:48 AM
#7
Re: Finding the string of number present inside brakects after a keywrod in a file
Thanks a lot. But i am using your previous technique through which i get the input in "integer" form and then i convert it into "string". Using that way also, i am able to remove and extra whitespace. This strategy is also ok?
-
April 25th, 2014, 09:51 AM
#8
Re: Finding the string of number present inside brakects after a keywrod in a file
Yes - it just makes the process slightly slower.
All advice is offered in good faith only. All my code is tested (unless stated explicitly otherwise) with the latest version of Microsoft Visual Studio (using the supported features of the latest standard) and is offered as examples only - not as production quality. I cannot offer advice regarding any other c/c++ compiler/IDE or incompatibilities with VS. You are ultimately responsible for the effects of your programs and the integrity of the machines they run on. Anything I post, code snippets, advice, etc is licensed as Public Domain https://creativecommons.org/publicdomain/zero/1.0/ and can be used without reference or acknowledgement. Also note that I only provide advice and guidance via the forums - and not via private messages!
C++23 Compiler: Microsoft VS2022 (17.6.5)
-
April 25th, 2014, 10:18 AM
#9
Re: Finding the string of number present inside brakects after a keywrod in a file
This will give you the numbers as a string without the leading space(s) and without the overhead of all the copying from converting to/from an integer irrespective of how many spaces there are between them.
Code:
const string nand_str = "NAND(";
const string nline = "15 = NAND( 9,6, 2, 8, 10,23 )";
size_t nand,
del;
if ((nand = nline.find(nand_str)) != string::npos)
nand += nand_str.length();
for (nand = nline.find_first_not_of(" ", nand); nand != string::npos; nand = nline.find_first_not_of(" ", del))
if ((del = nline.find_first_of(",)", nand)) != string::npos)
cout << nline.substr(nand, del++ - nand) << endl;
Last edited by 2kaud; April 25th, 2014 at 10:25 AM.
All advice is offered in good faith only. All my code is tested (unless stated explicitly otherwise) with the latest version of Microsoft Visual Studio (using the supported features of the latest standard) and is offered as examples only - not as production quality. I cannot offer advice regarding any other c/c++ compiler/IDE or incompatibilities with VS. You are ultimately responsible for the effects of your programs and the integrity of the machines they run on. Anything I post, code snippets, advice, etc is licensed as Public Domain https://creativecommons.org/publicdomain/zero/1.0/ and can be used without reference or acknowledgement. Also note that I only provide advice and guidance via the forums - and not via private messages!
C++23 Compiler: Microsoft VS2022 (17.6.5)
Tags for this Thread
Posting Permissions
- You may not post new threads
- You may not post replies
- You may not post attachments
- You may not edit your posts
-
Forum Rules
|
Click Here to Expand Forum to Full Width
|