Integer Range

[quorsum]

Hello

Declaring an __int64 or long long in VS2010 has the same range as an int while double works fine.

Checked MSDN over and over and can see no reason why this data range should not be 64 bit.

Any help is much appreciated.

[VictorN]

What is your system?
What did you expect?
What did you get instead?
Some code snippet would also help

[quorsum]

System: 32 bit windows 7 Visual Studio 2010
Expected 64 bit range (as double works fine)
got 32 bit range

[2kaud]

What does sizeof(__int64) give?

With my VS2010 this program

#include <iostream>
using namespace std;

int main()
{
	cout << sizeof(long long) << endl;
}

produces 8 (ie 64 bit) for both 32 and 64 bit builds

[quorsum]

Same here, sizeof(long long)==8

But when I assign 5000000000 to the variable I get 705032704.

[VladimirF]

But when I assign 5000000000 to the variable I get 705032704.

As Victor noted, "Some code snippet would also help"
HOW do you assign that value to that variable?

P.S. Here is a short demo - can you see the difference?

long long ll_1 = 5000000000;
long long ll_2 = 50000*100000;

[2kaud]

Well on my VS2010 this

#include <iostream>
using namespace std;

int main()
{
	cout << sizeof(long long) << endl;

	long long ll =  5000000000;

	cout << ll << endl;
}

produces

8
5000000000

??

[quorsum]

Thanks 2kaud

I always suspected something fishy with my system. But what is the explanation I wonder.

[quorsum]

VladimirF

long long test=5000000000;

[Igor Vartanov]

#include <windows.h>
#include <stdio.h>

int main()
{
    __int64  i64 = 5000000000;
    long long ll = 6000000000;

    printf("i64 (%li) = %I64i\n", sizeof(i64), i64);
    printf(" ll (%li) = %lli\n",  sizeof(ll),   ll);

    return 0;
}

J:\Temp\76>cl 76.cpp
Microsoft (R) 32-bit C/C++ Optimizing Compiler Version 16.00.40219.01 for 80x86
Copyright (C) Microsoft Corporation.  All rights reserved.

76.cpp
Microsoft (R) Incremental Linker Version 10.00.40219.01
Copyright (C) Microsoft Corporation.  All rights reserved.

/out:76.exe
76.obj

J:\Temp\76>76.exe
i64 (8) = 5000000000
 ll (8) = 6000000000

[VladimirF]

The next question is: how do you check the value after that assignment?

[OReubens]

Thanks 2kaud

I always suspected something fishy with my system. But what is the explanation I wonder.

YOU are doing something wrong, or YOU are interpreting results the wrong way.
if your system really was that fishy, it wouldn't even be able to boot into windows.

So as has been asked several times.
Produce actual code that either SHOWS the error, or screenshot of how you think you get that wrong answer

[razzle]

long long test=5000000000;

To denote a long long literal you need to add one of the suffixes l or L like

long long test = 5000000000L;

[VladimirF]

To denote a long long literal you need to add one of the suffixes l or L...

As I understand it, you only need to use these suffixes if the value may get misinterpreted.
Here, the long long value is assigned to long long variable; works for me without the suffix.

[razzle]

As I understand it, you only need to use these suffixes if the value may get misinterpreted.
Here, the long long value is assigned to long long variable; works for me without the suffix.

That works for me too.

But there's a certain amount of implementation dependency at play here and it's never wrong to be explicit about the literal type.

Also it seems in C++ 11 it's preferred to let the variable type be deducted from the literal type rather than the other way around like,

auto test = 5000000000L;

or

auto test = static_cast<long long>(5000000000);