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January 3rd, 2023, 12:11 AM
#1
adding + 1 with strlen?
What does the following code do?
why the code is adding + 1 with strlen?
Code:
v4 = (char *)malloc(0x400u);
strlen(v4) + 1;
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January 3rd, 2023, 02:20 AM
#2
Re: adding + 1 with strlen?
The +1 is necessary to count the \0 at the end of the string.
"abc" has a strlen result of 3, but it is stored in memory as "abc\0".
So if you wanted to allocate space to store "abc", you would need 4 bytes to do it.
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January 3rd, 2023, 04:34 AM
#3
Re: adding + 1 with strlen?
Note that malloc() returns a pointer to uninitialised storage. If the memory pointed to by v4 after malloc() is not initialised before use, it is unknown to what v4 points. Unless v4 memory is initialised between the malloc() and strlen() statements, the result of strlen() is unknown.
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C++23 Compiler: Microsoft VS2022 (17.6.5)
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