compile only one .cpp file???

[jdqie]

I'm fairly new to C++, so everything I do is with a single .cpp file. When I used the Bloodshed Dev C++ IDE, I was able to compile and run a single source file. I recently started using Visual C++ 2008 (express edition, if that matters) and now it seems like I can not compile a single file--I have to stick it inside a project in order to compile it. Is there a way around this? With Visual C++ can I compile a single .cpp file without using a "project"?

Any help would be greatly appreciated. Thanks!

[VictorN]

It doesn't make any sense IMHO, to compile a single file without any project.

[memeloo]

It doesn't make any sense IMHO, to compile a single file without any project.

i'm sorry, but you're comment either... he didn't ask whether it makes sense but how to do it, so probalby it makes sense in his case

@jdqie
http://msdn.microsoft.com/en-us/library/ms235639.aspx

[VictorN]

i'm sorry, but you're comment either... he didn't ask whether it makes sense but how to do it, so probalby it makes sense in his case

@jdqie
http://msdn.microsoft.com/en-us/library/ms235639.aspx

Well, it is interesting info (and, probably, will be useful for OP)!

As for me - I don't like using command prompt when I can use VS IDE with all its features as debugging, break points, watch, output and other windows and so on.

[CoolPG]

As for me - I don't like using command prompt when I can use VS IDE with all its features as debugging, break points, watch, output and other windows and so on

++i

[memeloo]

i = (isEasier == true ? i-1 : i+1)

[VictorN]

i = (isEasier == true ? i-1 : i+1)

I prefer:

if(isEasier)
     ++i;
else
     --i;

[laserlight]

How about:

const int increments[] = {1, -1};
i += increments[isEasier];

[VictorN]

How about:

const int increments[] = {1, -1};
i += increments[isEasier];

It won't work for bool isEasier, only for int for which only 0 and 1 are allowed...
So it would be much more complicated to implement.

[laserlight]

It won't work for bool isEasier, only for int for which only 0 and 1 are allowed...

There exists an implicit conversion from bool to int whereby false is converted to 0 and true is converted to 1.

[VictorN]

There exists an implicit conversion from bool to int whereby false is converted to 0 and true is converted to 1.

Good to know it!
Thank you!

[memeloo]

How about:

const int increments[] = {1, -1};
i += increments[isEasier];

nice

another one:

i += 1 * (isEasier * -1);

[laserlight]

another one:

That won't work: if isEasier is false, the expression evaluates to 0, not -1.

But I realise that my hack has a similiar bug: the array elements should be swapped.

Anyway, we could adapt your example:

i += isEasier * -2 + 1;

[memeloo]

That won't work: if isEasier is false, the expression evaluates to 0, not -1.

****! how could i not see it :\

[OReubens]

i += !isEasier - isEasier;


Probably the best one to make people scratch their heads twice figuring out what this does.