Pointer Question? (Small fun about pointer :D)

[DoDucTruong]

Sometimes I am crazy about pointers in C/C++, but I love it.
Today I post this small fun about pointers

Could you say what is printed on the consol window after the program finishs and explain why? How many bytes of memory are not free?

#include <stdio.h> 
#include <memory.h> 
void SetText(void***** p, char v){memcpy(****p,&*&v,1);} 
void UcaseOrLcase(char& v, char u){v-=32;u-=32;} 
int main(int argc, char* argv[]) 
{ 
   char cs[5][3]={'h','l','e','l','o','m','m','r','r','r','s','e','o','y',' '}; 
   char (*c2)[3] = &cs[2]; 
   char (*c3)[3] = cs + 3; 
   char outtext[15]={0}; 
   char *****tmp; 
   tmp=new char**** [1]; 
   *tmp=new char*** [1]; 
   **tmp=new char** [1]; 
   ***tmp=new char* [2]; 
   ****tmp=new char[6]; 
   memcpy(tmp+(c3-c2),*c2,1); 
   memcpy(*tmp+1,&cs[0][2],1); 
   memcpy(**tmp+1,*(cs+3),1); 
   memcpy(***tmp+2,0[c3],1); 
   SetText((void*****)tmp,cs[4][1]); 
   outtext[0]=(char)*(tmp+1); 
   outtext[1]=(char)*(*tmp+1); 
   outtext[2]=(char)*(**tmp+1); 
   outtext[3]=(char)*(***tmp+2); 
   outtext[4]=(char)*(****tmp); 
   outtext[5]=*(*(cs+(int)c3-(int)c2+1)+2); 
   outtext[6]=0; 
   UcaseOrLcase(*outtext,outtext[5]); 
   char *****tmp2=new char**** [20];    
   *tmp2=(char****)(tmp2+1); 
   *(tmp2+1)=(char****)(tmp2+2); 
   *(tmp2+2)=(char****)(tmp2+3); 
   *(tmp2+3)=(char****)(tmp2+4); 
   4[tmp2]=(char****)&*&5[tmp2]; 
   memcpy(****tmp2,"world\n\0",6); 
   memcpy((tmp2+4),"christmas\n\0",11);    
   UcaseOrLcase(0[****tmp2],(char)*(tmp2+4)); 
   printf("%s%s",outtext,(char*)*&*&*&*&*&****tmp2); 
   return 0; 
}

Have fun
(Tested in VC++ 6.0)