PHP MySQL problem

[NewtoPHP]

Hello guys,
I am having a search script which suppose to take results out of my mysql
database and display on a page 10 results each
if the results are more then 10 it should create another page
or pages with Next >> and Prev << link so anyone can move
forward and backward on those results page.

This script do everything fine counting total records display's 1 to 10
records on first page but at second location on same page i want it to daisplay
Showing results 1 to 10 of total records found it show 5 to 14, ant it
displays a link to Next which is not working.

Here is the code to generate pages please have a look and let me
know where I am wrong.

// begin to show results set
echo " found  $numrows results <p>";
$count = 1 + $s;

// now you can display the results returned
  while ($row= mysql_fetch_array($result)) {

  $title = $row["sname"];
  $url = $row["url"];
  $message = $row["massage"];
//&nbsp;<a href=\"$row['url']\">"$row['sname']</a><br /> 
$row['massage']<br><hr>'\

  echo "$count.)&nbsp";
  echo "<b><a href=\"$url\" target=\"_blank\">$title</a></b>";
  echo "<br>";
  echo "$message<br><hr height=12 color=lightblue><br>";
  $count++;

  }

$currPage = (($s/$limit) + 1);

//break before paging
  echo "<br />";

  // next we need to do the links to other results &lt;&lt;
  if ($s>=1) { // bypass PREV link if s is 0
  $prevs=($s-$limit);
  print "&nbsp;<a href='{$_SERVER['PHP_SELF']}?s=$prevs&q=$var'> <<<
  Prev 10</a>&nbsp&nbsp;";
  }

// calculate number of pages needing links
//  $s=intval($numrows/$limit);
  $s=ceil($numrows/$limit);


// $s now contains int of pages needed unless there is a remainder from 
division

  if ($numrows%$limit) {
  // has remainder so add one page
  $s++;
  }

// check to see if last page
  if (!((($s+$limit)/$limit)==$s) && $s!=1) {

  // not last page so give NEXT link  $PHP_SELF &gt;&gt;
  $news="$s+$limit";

  echo "&nbsp;<a href='{$_SERVER['PHP_SELF']}?s=$news&q=$var'>Next 10 >>> 
</a>";

  }

$a = $s+$limit;
  if ($a > $numrows) { $a = $numrows; }
$b = $s+1;
  echo "<p>Showing results $b to $a of $numrows</p>";
include ('footer.inc');
?> 

Thank You