Why getting male sex symbol? char push help

[BreakIn]

I need to add the operands and then push the result onto the stack, when pushed; it pushes a symbol (add 6 and 5, you get the male symbol). What am I doing wrong, I need the symbol to be 11 (when using 6 and 5)?

stack myStack;
char arg1;  // this will hold the left operand.
char arg2; //this will hold the right operand.
char result; // result of every calculation, to be pushed onto stack.


int main()
{
	string s1;
	cout << "Input the numbers followed by operator(s): " << endl;
	cin >> s1;

	for (int i=0;s1[i]!='\0';i++) 
	{
		if (isdigit(s1[i]))  //used isdigit to check if number, if true; push.
			myStack.push(s1[i]);
		else if(s1[i]=='+'){
			//int x = int(mystring[i]) - 48;
			myStack.pop(arg1); //pops operand off top of stack and into arg1 which is a char data
			myStack.pop(arg2); //pops operand off top of stack and into arg2 which is a char data
			result = int(arg1)-48 + int(arg2)-48;  
			//if result is initialized as char, pushes symbol and result is symbol
			//if result is initialized as int, pushes symbol but result is correctly outputed below
			cout << "arg1 and arg2 and result: " << arg1 << " " << arg2 << " " << int(result) << endl;  //The numbers are correct here , 6 5 11.  If int() not used, male sex symbol is result.

			myStack.push(result); //HOW TO INPUT RESULT????? tried using int(result) and //intresult-48, both do not give the correct 11 when '65+' is unput.
		} else
			cout << "else called from client" << endl;
			
	}

	myStack.displayAll(); //displays contents of stack which should be 11 but comes our as the male sex symbol when inputed '65+' into program. should be 11.
}