Simple passing pointers as an argument

[ejohns85]

Hello,

In my code, I create a 3-element integar array, using the function CreateArray(). I then want to pass this array to another function, which will inspect the values of this array. Here is what I have tried:

int* CreateArray();
void CheckValues(int* an_array);

int main()
{
	int* my_array = CreateArray();
	CheckValues(my_array);
	return 0;
}

int* CreateArray()
{
	int my_array[3];
	my_array[0] = 5;
	my_array[1] = 10;
	my_array[2] = 25;
	return my_array;
}

void CheckValues(int* an_array)
{
	int a = an_array[0];
	int b = an_array[1];
	int c = an_array[2];
}

The problem is, in CheckValues(int* an_array), the values of a, b and c are not 5, 10 and 15 as expected, bu they are all -858993460.

I don't know why this is. I pass a pointer to my array, and then check the values which the pointer is pointing to. What's wrong?

I know that when an argument is passed to a function, a copy is made of it, so the original variable is not modified. But in this case, if I a copy is made of the pointer, then the copy will still point to the same address, and should still therefore point to the correct values.

Any help?

Thanks!