Hi there!

I've got two questions about friend declarations.

1)

According to the 11.8.1 paragraph of C++03 standard:

The members of a nested class have no special access to members of an enclosing class, nor to classes or functions that have granted friendship to an enclosing class
How is it possible that a single function can grant friendship to a class ?

2)

My second question concerns a base-clause of a nested class.

We can read in C++0x standard draft (11.4.2 paragraph) that:

Declaring a class to be a friend implies that the names of private and protected members from the class granting friendship can be accessed in the base-specifiers and member declarations of the befriended class.
[ Example:

Code:
class A
{
    class B { };
    friend class X;
};

struct X : A::B //OK: A::B accessible to friend
{
    A::B mx; //OK: A::B accessible to member of friend
    class Y
    {
        A::B my; //OK: A::B accessible to nested member of friend
    };
};
—end example ]
It isn't mentioned in the example whether private and protected type names from the class granting friendship can be used in the base-clause of a nested class of the friend class (here it would be the base-clause of class Y).

I think they can, do you think so too ?

I can't check it by myself since I don't have any compatible with C++0x compilers...