How to find the architecture of the system using pointers?

[madhu542]

Hi,

I have a program (below)

int main() {
int x = 1;
char *y = (char *) &x;
printf("%d\n", *y);
}

The output will be either "0" or "1" depending on the architecture of the system.
When I executed on my system I got output as "1", now what is the architecture of my system is it 32 bit or 64 bit?