|
-
August 30th, 2002, 11:28 PM
#1
A question about #define
Hi, everyone!
Please look at the following statement,
--------
#define assert(x) ((void)0)
--------
What does the statement mean? What is the function
of "((void)0)" here?
Another question, there is a paramater "x" in the former
"assert(x)", why there is not a parameter in the latter
"((void)0)"?
Cheers,
George
Posting Permissions
- You may not post new threads
- You may not post replies
- You may not post attachments
- You may not edit your posts
-
Forum Rules
|
Click Here to Expand Forum to Full Width
|