Loading text lines cause memory corruption

[indiocolifa]

I'm trying to load a simple file with text lines on it and store on a proper structure. The code i'm working on is:

BOOL loadtextfile(char* filename, TEXTBUFFER* t)
{
    FILE* fp;
    char line[MAX_LINE];
    int i = 0;

    fp = fopen(filename, "r");
    if (!fp)
        return FALSE;

      fgets(line, MAX_LINE, fp);
    while (!feof(fp))
    {
        t->linebuffer[i] = (char*)xmalloc(MAX_LINE);
        line[strlen(line)-1] = '\0';    /* quit CR */
        strncpy(t->linebuffer[i], line, strlen(line) );
        i++;
        fgets(line, MAX_LINE, fp);
    }

    t->numTextLines = i;
    fclose(fp);

    return TRUE;
}

A TEXTBUFFER is a struct defined as:

typedef struct
{
    int numTextLines;                   /* numero de lineas de texto fuente*/
    char* linebuffer[];

} TEXTBUFFER;

I don't know how reading lines (from a proper formatted lines) trash other memory areas...

[j0nas]

You need to allocate the array size (linebuffer) as well. You can't do that without knowing the number of read in lines.

Maybe you should store the lines in a linked-list instead.

typedef struct
{
    int numTextLines;                   /* numero de lineas de texto fuente*/
    LINKEDLIST *head;
    LINKEDLIST *tail;
} TEXTBUFFER;

typedef struct _LINKEDLIST
{
    char *str;
    struct _LINKEDLIST *next;
} LINKEDLIST;

[VladimirF]

As j0nas said, you might be writing past your "t" array.
Also, in this code:

line[strlen(line)-1] = '\0';    /* quit CR */

if your line is empty, you will write '\0' right before it.
P.S. Does the line read with fgets() contain CR at the end?

[Calculator]

Yes, a linked list seems suitable for this. If it is opened in text mode, it will only have an LF. If it is in binary mode, it will have a CRLF. I would also say

while(fgets(line, MAX_LINE, fp))

Also, if you are just going to be doing

t->linebuffer[i] = (char*)xmalloc(MAX_LINE);

I don't see why you're dynamically allcoating it. I'd allocate enough memory for strlen(line) + 1

>> if your line is empty, you will write '\0' right before it.

I think if the line is empty, it will look like "\n\0".