A few things...

[Frankmms]

Ok so just a few code tidbits needed - a function to add all the odd integers from 1 to n, a function that adds all the integers up from 1 to a number equalling that number such as 1 + 2 + 3 + 4 if they enter 10, and a function that adds the digits of a negative number such as 3 if the number is -12 or 5 if the number is -23.

Thanks please

[Bnt]

Hi,

Have you tried to do this by yourself yet? If so please post your code and say what you are having a problem with and then we'll be able to help you.

[masher]

They aren't all that hard to do.

Took me 30 minutes this morning to cobble some things together...

[Frankmms]

I got the first two but for the next question, which is really just finding the sums of a NONnegative number, I jotted down the stuff below then got too confused:

public class test{
int i = 0;
public static int lube(int n){
while (i < n){
i = (n / 100) + (n / 10 % 10) + (n % 10);}
return i;}}

Is it something like that?

[wildfrog]

Can you please elaborate on your last assignment?

-petter

[masher]

I got the first two but for the next question, which is really just finding the sums of a NONnegative number, I jotted down the stuff below then got too confused:

public class test{
int i = 0;
public static int lube(int n){
while (i < n){
i = (n / 100) + (n / 10 % 10) + (n % 10);}
return i;}}

Is it something like that?

Have a look at this:

 int addDigits(int num)
   {
      int sum = 0;

      while(num > 0)
      {
         sum += (num % 10); // gets the last digit and adds it to the sum

         num = num / 10; //relies on integer division to move the number down.
      }

      return sum;
   }

[Bnt]

You could also convert the number to a String, strip of the minus sign, convert all the characters back to integers and then add them.

public int addDigits(int num){
	String s = String.valueOf(num);
	String[] chars = s.split("");
	
	int sum = 0;
	for(int i = 0; i < chars.length; i++){
		try{
			sum += Integer.parseInt(chars[i]);
		}catch(NumberFormatException nfe){
			//Catch block will catch the 
			//Exception that gets thrown when 
			//trying to convert the minus sign 
			//to an int and will ignore it
		}
	}
	
	return sum;
}

[Frankmms]

Taking the sum and dividing it by 10 each time the loop runs then modding to get the last number looks like the easiest way to do it Thanks all.

[Frankmms]

Haha back again...One day this thread will be hundreds of pages long :O

Ok so I'm supposed to create a triangle out of ***s, given a number of rows, so if you put in 3, it makes the triangle 3 rows tall, 4 is 4 rows tall, etc, looking like:

3 spaces *
2 spaces ***
1 space *****
0space*******

I have no idea how to go about even starting this

[dlorde]

A new problem should start a new thread...

Think about how you would do it if you had to use a typewriter and paper (i.e. line by line). Then translate those steps into code.

Give me a fish and I eat for a day. Teach me to fish and I eat for a lifetime...
Chinese proverb

[Frankmms]

Ok so I'm thinking

public int makeTriangle(int rows){
for (i=1; i > rows; i++){
System.out.println("Okay now I get lost");}}

[_uj]

Ok so just a few code tidbits needed - a function to add all the odd integers from 1 to n, a function that adds all the integers up from 1 to a number equalling that number such as 1 + 2 + 3 + 4 if they enter 10, and a function that adds the digits of a negative number such as 3 if the number is -12 or 5 if the number is -23.

Thanks please

Well, to become a programmer you need to know basic math. The one builds on the other, stupid.

[Frankmms]

It's not math I have trouble with, it's converting math into Java, stupid.

[_uj]

It's not math I have trouble with, it's converting math into Java, stupid.

So what's the problem then, smartie?

[Frankmms]

It's not math I have trouble with, it's converting math into Java, stupid.

I also don't get the adding spaces in front of the ***s to make it a centered triangle, maybe another loop, but that's the problems I'm having.