another float/int/for question

[lab1]

Hello I have a loop like this:

int j;
for(float i = 0.0f, j = 0; i <= 1.0f; i=i+(1.0f/CDF_RESOLUTION, j++))
intervalEdges.push_back(j);

For some reason when I look at "j" value it is represented as a floating point number.

Any idea why? Is this the best way to try to do something like this??

Thanks!

[jfaust]

'for' begins another scope, allowing you to hide outer-scope variables.
'float i = 0.0f, j = 0;' defines two floats, i and j.

solution: set j = 0 before the loop:

int j = 0;
for(float i = 0.0f; i <= 1.0f; i=i+(1.0f/CDF_RESOLUTION, j++))

Jeff

[AvDav]

Did you put the brace in the right place? I guess

for(float i = 0.0f; i <= 1.0f; i=i+(1.0f/CDF_RESOLUTION, j++))

should be

for(float i = 0.0f; i <= 1.0f; i=i+(1.0f/CDF_RESOLUTION), j++)

Besides, you don't need the loop, and intervalEdges container perhaps:
you need to know what is the upper-bound of j right? [0, x], need to know x.
set a = 1.0f/CDF_RESOLUTION
x = int((1.0f - 0.0f)/a);

[Paul McKenzie]

Hello I have a loop like this:

int j;
for(float i = 0.0f, j = 0; i <= 1.0f; i=i+(1.0f/CDF_RESOLUTION, j++))
intervalEdges.push_back(j);

For some reason when I look at "j" value it is represented as a floating point number.

Any idea why? Is this the best way to try to do something like this??

Thanks!

This is not part of your subject line, but there are far more worse issues with this code that were discussed here already.

http://www.codeguru.com/forum/showthread.php?t=408602
https://www.securecoding.cert.org/co...+loop+counters
http://www.math.ucsd.edu/~sbuss/Cou...atingperils.pdf

Regards,

Paul McKenzie