new to malloc conversion

[bitshifter420]

I can allocate a multi-subscripted array using the new operator like this,
but how do i write it using the malloc function instead.

float (*ptr)[3] = NULL;
int size = 64;

void create(void)
{
   ptr = new float [size][3];
}

void destroy(void)
{
   if(ptr)
   {
      delete [] ptr;
      ptr = NULL;
   }
}

[aLiNuSh]

Are you trying to do something like this? I'm a little confused with your float (*ptr)[3] declaration syntax...

//	I want to create a [m][n] matrix in C++
int * createMatrix (int m, int n)
{
	int **matrix = new int *[m];
	
	for (int i = 0; i < m; i++)
	{
		matrix[i] = new int[n];
	}
}

//	I want to create a [m][n] matrix in C
int * createMatrix (int m, int n)
{
	int **matrix = malloc (m * sizeof (int *));
	int i;
	for (i = 0; i < m; i++)
	{
		matrix[i] = malloc (n * sizeof (int));
	}
}

I didn't write the deleteMatrix () functions but they're pretty easy to implement...

[Lindley]

^You may have to explicitly cast the result of malloc to (int*). Some compilers don't like automatic void* conversion. (Technically I think C allows it, C++ doesn't.)

[aLiNuSh]

^You may have to explicitly cast the result of malloc to (int*). Some compilers don't like automatic void* conversion. (Technically I think C allows it, C++ doesn't.)

As far as I know, C allows this implicit conversion but C++ is a little stricter so if he's using malloc() with C++ (why not use new?) he will need to cast the void pointer to an int pointer.

[Lindley]

(why not use new?)

Sometimes it helps to make explicit the fact that no constructor is being called. It's something you have to be careful with, though.