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February 28th, 2008, 07:12 AM
#12
Re: codebreaking program
What´s this all about?
Code:
for (int x = 0; x <= 512; x++){
if (code[x] != 'a'){
code[x] = decry[0];
}
if (code[x] != 'b'){
code[x] = decry[1];
}
if (code[x] != 'c'){
code[x] = decry[2];
}
if (code[x] != 'd'){
code[x] = decry[3];
}
if (code[x] != 'e'){
code[x] = decry[4];
}
if (code[x] != 'f'){
code[x] = decry[5];
}
if (code[x] != 'g'){
code[x] = decry[6];
}
if (code[x] != 'h'){
code[x] = decry[7];
}
if (code[x] != 'i'){
code[x] = decry[8];
}
if (code[x] != 'j'){
code[x] = decry[9];
}
if (code[x] != 'k'){
code[x] = decry[10];
}
if (code[x] != 'l'){
code[x] = decry[11];
}
if (code[x] != 'm'){
code[x] = decry[12];
}
if (code[x] != 'n'){
code[x] = decry[13];
}
if (code[x] != 'o'){
code[x] = decry[14];
}
if (code[x] != 'p'){
code[x] = decry[15];
}
if (code[x] != 'q'){
code[x] = decry[16];
}
if (code[x] != 'r'){
code[x] = decry[17];
}
if (code[x] != 's'){
code[x] = decry[18];
}
if (code[x] != 't'){
code[x] = decry[19];
}
if (code[x] != 'u'){
code[x] = decry[20];
}
if (code[x] != 'v'){
code[x] = decry[21];
}
if (code[x] != 'w'){
code[x] = decry[22];
}
if (code[x] != 'x'){
code[x] = decry[23];
}
if (code[x] != 'y'){
code[x] = decry[24];
}
if (code[x] != 'z'){
code[x] = decry[25];
}
Does the snippet do what you intend to? Furthermore, using a switch statement enhances readability.
- Guido
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