Function pointers...I don't know what they are

[potatoCode]

Hello spetsacdc,

I'm a beginner here, but like 7stud said, can't it be that you're leaving something out of the context?

because, you said if statement is now allowed (and I assume neither is switch), but you said a user is prompted to enter a choice, how is this possible without a condition?

Here's my best guess on what must be done.
1. both functions must give(not necessairly return) same End Result.
2. we need to create 5 seperate files. one for main.cpp, 2 for g.h/g.cpp, and 2 for f.h/f.cpp.
3. Let's assume "avoid two versions of the source code" as "One definition in one function is not seen in the other.
4. One of either function must accept a pointer as an ARGUMENT.
5. No conditional statements are allowed.

given all these, I believe (hopefully) either of the functions must call the other.
for instance; g.cpp would be something like

#include "g.h"
#include "f.h"

// pass by pointer
int g(int* y)
{
     return f(*y);
     }

and f.cpp

// pass by value
int f(int y)
{
     int twice(0);
     twice = y * 2;
        
     return twice;
     }

as you can see, we did not write two versions of the same source code(#3)
and both functions give the same result(#1) and satisfies #4 and the rest with the remainding header files.

but somehow,
I have a feeling (as usual...) what 7stud and Lindley said is more likely to be your answer.

see ya!