function template

[ptg]

im working on a function template. i just want to know if im doing it right so far. i put comments on parts im not sure of

#include<iostream>
using namespace std;

template <typename isEqualTo = int> // is this a template header with one formal type of parameter
// how would i write a header for function template isEqualTo
{
return arg1==arg2;
}

int main(){
int a;
int b;
cout<<"enter two interger values: ";
cin>>a>>b;
cout<<a<<"and"<<b<<"are"
<<( ?"equal":"not equal")<<'\n';
return 0;
}

[souldog]

I think you have this in mind

template <typename T = int>
bool AreEqual(const T arg1, const T arg2)
{
return arg1==arg2;
}

[exterminator]

I think you have this in mind

template <typename T = int>
bool AreEqual(const T arg1, const T arg2)
{
return arg1==arg2;
}

You can't have default template arguments with "function" templates. Making that a functor might solve the problem though.

[Hermit]

You can't have default template arguments with "function" templates. Making that a functor might solve the problem though.

I can't imagine the purpose of a default template argument in this case anyway, since the type appears in the parameter list of the function and can be automatically deduced.

The point about using a functor is a good one, though, especially considering STL already provides such a functor: std::equal_to<T>

[exterminator]

I can't imagine the purpose of a default template argument in this case anyway, since the type appears in the parameter list of the function and can be automatically deduced.

The point about using a functor is a good one, though, especially considering STL already provides such a functor: std::equal_to<T>

That's correct. I was just considering that it was for illustration purpose as an example of how to write a function template taking a type argument.

[souldog]

You can't have default template arguments with "function" templates. Making that a functor might solve the problem though.

Yah, that is what I get for copy and paste without thinking

[ptg]

well i get an error saying that its only allowed using a class template. is the only way to use a template is thru a class?
also would that template work for both char and doubles?
or am i getting that error because i havent called the template in the main?

#include<iostream>
using namespace std;

template <typename T = int>
bool AreEqual(const T arg1, const T arg2){
	return arg1==arg2;
}

int main(){
	int a;
	int b;

	cout<<"enter two interger values: ";
	cin>>a>>b;
	cout<<a<<"and"<<b<<"are"
		<<(             ?"equal":"not equal")<<'\n';

	char c;
	char d;

	cout<<"\nenter two character values: ";
	cin>>c>>d;
	cout<<c<<"and"<<d<<"are"
		<<(               ?"equal":"not equal")<<'\n';

	double e;
	double f;

	cout<<"\nenter two double values: ";
	cin>>e>>f;
	cout<<e<<"and"<<f<<"are"
		<<(               ?"equal":"not equal")<<'\n';
	return 0;
}

[exterminator]

Yah, that is what I get for copy and paste without thinking

Good to see you, one of the old-timers, back!

[exterminator]

template <typename T = int>
bool AreEqual(const T arg1, const T arg2){
	return arg1==arg2;
}

change above to:

template <typename T>
bool AreEqual(const T& arg1, const T& arg2){ //change to reference if complex types might be compared as well
	return arg1==arg2;
}

Or you could simply use std::equal_to<T> as suggested by Hermit. Follow the link he posted.

[souldog]

Good to see you, one of the old-timers, back!

Thanks. Nice to be back