How to determine ranks

[tejen]

I have an assignment where i have to to determine ranks of 5 runners according to their times that were input. The only way of doing this that I know is by using if and else if statements. and I think there are over 120 permuations for 12345 so how do i determine the ranks of 5 people when there are over 120 permuations? Does C++ have way of making this easier. Im very new to this and any help would be appreciated. Thank you!


#include <iostream>
#include <iomanip>
#include <fstream>
using namespace std;
int main()
{
ofstream outputfile;
outputfile.open("c:\\Project_2\\M20349431_output_2.txt");
ifstream infile;
infile.open("c:\\Project_2\\M20349431_output_2.txt");

//Define variables
const int SIZE = 21;
char name1[SIZE], name2[SIZE], name3[SIZE], name4[SIZE], name5[SIZE];
double time1, time2, time3, time4, time5;

//Display the purpose oof this program
cout<<"This program will determine the ranks of 5 runners according to their time."<<endl;
cout<<endl;

//Request the names and times of each runner.
cout<<"1. Enter the name of the runner"<<endl;
cin.getline(name1, SIZE);
cout<<endl; //For line spacing


cout<<"2. Enter the name of the next runner"<<endl;
cin.getline(name2, SIZE);
cout<<endl; //For line spacing

cout<<"3. Enter the name of the next runner"<<endl;
cin.getline(name3, SIZE);
cout<<endl; //For line spacing

cout<<"4. Enter the name of the next runner"<<endl;
cin.getline(name4, SIZE);
cout<<endl; //For line spacing

cout<<"5. Enter the name of the next runner"<<endl;
cin.getline(name5, SIZE);
cout<<endl; //For line spacing



//Request the time of each runner
cout<<"Enter the time for "<<name1<<endl;
cin>>time1;

if(time1 <= 0) //Check for negative numbers or 0)
{ cout<<"Error! Invalid number. You must enter a number greater than 0"<<endl; //Display "Error" message if a invalid number is entered
cin>>time1;
}

cout<<endl; //For line spacing


cout<<"Enter the time for "<<name2<<endl;
cin>>time2;

if(time2 <= 0) //Check for negative numbers or 0)
{
cout<<"Error! Invalid number. You must enter a number greater than 0"<<endl; //Display "Error" message if a invalid number is entered
cin>>time2;
}

cout<<endl; //For line spacing

cout<<"Enter the time for "<<name3<<endl;
cin>>time3;

if(time3 <= 0) //Check for negative numbers or 0)
{
cout<<"Error! Invalid number. You must enter a number greater than 0"<<endl; //Display "Error" message if a invalid number is entered
cin>>time3;
}

cout<<endl; //For line spacing

cout<<"Enter the time for "<<name4<<endl;
cin>>time4;

if(time1 <= 0) //Check for negative numbers or 0)
{ cout<<"Error! Invalid number. You must enter a number greater than 0"<<endl; //Display "Error" message if a invalid number is entered
cin>>time4;
}

cout<<endl; //For line spacing

cout<<"Enter the time for "<<name5<<endl;
cin>>time5;

if(time1 <= 0) //Check for negative numbers or 0)
{ cout<<"Error! Invalid number. You must enter a number greater than 0"<<endl; //Display "Error" message if a invalid number is entered
cin>>time5;
}

cout<<endl; //For line spacing



//Determine the rank of each runner according to the times that were entered



if(time1 < time2 && time2 < time3 && time3 < time4 && time4 < time5)
{
outputfile<<"\nThe ranks of the runners according to their times\n";
outputfile<<"---------------------------------------------------\n";

outputfile<<"Rank 1 is "<<setw(25)<<name1<<" With the time of: "<<setw(6)<<time1<<endl;

outputfile<<"Rank 2 is "<<setw(25)<<name2<<" With the time of: "<<setw(6)<<time2<<endl;

outputfile<<"Rank 3 is "<<setw(25)<<name3<<" With the time of: "<<setw(6)<<time3<<endl;

outputfile<<"Rank 4 is "<<setw(25)<<name4<<" With the time of: "<<setw(6)<<time4<<endl;

outputfile<<"Rank 5 is "<<setw(25)<<name5<<" With the time of: "<<setw(6)<<time5<<endl;
}

else if(time5 < time4 && time4 < time3 && time3 < time2 && time2 < time1)
{
outputfile<<"\nThe ranks of the runners according to their times\n";
outputfile<<"---------------------------------------------------\n";

outputfile<<"Rank 1 is "<<setw(25)<<name5<<" With the time of: "<<setw(6) <<time5<<endl;

outputfile<<"Rank 2 is "<<setw(25)<<name4<<" With the time of: "<<setw(6)<<time4<<endl;

outputfile<<"Rank 3 is "<<setw(25)<<name3<<" With the time of: "<<setw(6)<<time3<<endl;

outputfile<<"Rank 4 is "<<setw(25)<<name2<<" With the time of: "<<setw(6)<<time2<<endl;

outputfile<<"Rank 5 is "<<setw(25)<<name1<<" With the time of: "<<setw(6)<<time1<<endl;
}

and so on....... But then I realized there are about 120 permuations for 12345 and i would have to repeat this process over 120 times Is their an easier way to determine ranks, or do i have to do this 120 times. Please help

[Skizmo]

char name1[SIZE], name2[SIZE], name3[SIZE], name4[SIZE], name5[SIZE];
double time1, time2, time3, time4, time5;

Turn these into an array and you can transform your code by using loops.

[tejen]

Ok, but how do I Input the names of each of 5 runners and their respective times.
This is what I tried:

const int runners = 5;
char name1[21], name2[21], name3[21], name4[21], name5[21];
double time[runners];
int rank;

//Display the purpose oof this program
cout<<"This program will determine the ranks of 5 runners according to their time."<<endl;
cout<<endl;

//Request the names and times of each runner.
cout<<"1. Enter the name of the runner"<<endl;
cin>>name1[21];
cout<<endl; //For line spacing


cout<<"2. Enter the name of the next runner"<<endl;
cin>>name2[21];
cout<<endl; //For line spacing

cout<<"3. Enter the name of the next runner"<<endl;
cin>>name3[21];
cout<<endl; //For line spacing

cout<<"4. Enter the name of the next runner"<<endl;
cin>>name4[21];
cout<<endl; //For line spacing

cout<<"5. Enter the name of the next runner"<<endl;
cin>>name5[21];
cout<<endl; //For line spacing

I uploaded an example of what my output file is suppose to look like and the screenshot of the program after I type in the first name and hit enter.

[cilu]

This is not correct.

cout<<"1. Enter the name of the runner"<<endl;
cin>>name1[21];
cout<<endl; //For line spacing

You probably mean:

cout<<"1. Enter the name of the runner"<<endl;
cin>>name1;
cout<<endl; //For line spacing

However, get rid of this char arrays and use std::string.
http://www.codeguru.com/cpp/cpp/stri...cle.php/c13267

[tejen]

Thanks for the tips. I changed my entire source code and used arrays instead, but I still don't know how to determine ranks for 5 people according to their lap times??? I'm not very familiar of using loops for doing this. again your help is appreciated.

#include <iostream>
#include <iomanip>
#include <fstream>
using namespace std;
int main()
{
ofstream outputfile;
outputfile.open("c:\\Project_2\\M20349431_output_2.txt");
ifstream infile;
infile.open("c:\\Project_2\\M20349431_output_2.txt");

//Define variables
const char runners = 100;
char names[100][runners];


//Display the purpose oof this program
cout<<"This program will determine the ranks of 5 runners according to their time."<<endl;
cout<<endl;

//Request the names of each runner.
cout<<"1. Enter the names of all the runners"<<endl;
cin>>names[0];
cout<<endl;
cin>>names[1];
cout<<endl;
cin>>names[2];
cout<<endl;
cin>>names[3];
cout<<endl;
cin>>names[4];
cout<<endl;

//Display the names
cout<<"The names you entered are:"<<endl;
cout<<names[0]<<endl;
cout<<names[1]<<endl;
cout<<names[2]<<endl;
cout<<names[3]<<endl;
cout<<names[4]<<endl;
cout<<endl;

//Request Time
cout<<"2. Enter the times for all the runners"<<endl;
cout<<endl;

const int times = 5;
double time[times];

cout<<"Enter the time for "<<names[0]<<endl;
cin>>time[0];
cout<<endl;

while(time[0] <= 0)
cout<<"Error! Time Must Be Greater Than Zero. Restart Program"<<endl;

cout<<"Enter the time for "<<names[1]<<endl;
cin>>time[1];
cout<<endl;

cout<<"Enter the time for "<<names[2]<<endl;
cin>>time[2];
cout<<endl;

cout<<"Enter the time for "<<names[3]<<endl;
cin>>time[3];
cout<<endl;

cout<<"Enter the time for "<<names[4]<<endl;
cin>>time[4];
cout<<endl;


//Display names and times together
cout<<"You entered:"<<endl;
cout<<endl;

cout<<setprecision(2)<<fixed;
cout<<left<<setw(20)<<names[0]<<" -------- "<<right<<setw(6)<<time[0]<<endl;
cout<<left<<setw(20)<<names[1]<<" -------- "<<right<<setw(6)<<time[1]<<endl;
cout<<left<<setw(20)<<names[2]<<" -------- "<<right<<setw(6)<<time[2]<<endl;
cout<<left<<setw(20)<<names[3]<<" -------- "<<right<<setw(6)<<time[3]<<endl;
cout<<left<<setw(20)<<names[4]<<" -------- "<<right<<setw(6)<<time[4]<<endl;

cout<<endl;

cout<<"Open the output file to view the results and the ranks of the all the runners"<<endl;


system("pause"); //Pause the program so that the user can view the results



return 0;

[Skizmo]

I'm not very familiar of using loops for doing this. again your help is appreciated.

cout<<"The names you entered are:"<<endl;
cout<<names[0]<<endl;
cout<<names[1]<<endl;
cout<<names[2]<<endl;
cout<<names[3]<<endl;
cout<<names[4]<<endl;
cout<<endl;

long lCnt;

cout<<"The names you entered are:"<<endl;
for (lCnt = 0; lCnt < 5; lCnt++)
{
   cout<<names[lCnt]<<endl;
}
cout<<endl;

[tejen]

cout<<"The names you entered are:"<<endl;
cout<<names[0]<<endl;
cout<<names[1]<<endl;
cout<<names[2]<<endl;
cout<<names[3]<<endl;
cout<<names[4]<<endl;
cout<<endl;

long lCnt;

cout<<"The names you entered are:"<<endl;
for (lCnt = 0; lCnt < 5; lCnt++)
{
   cout<<names[lCnt]<<endl;
}
cout<<endl;

This gives me the same output for the names, I need help determining rank 1, rank2, rank3, rank4 and rank5 according to the runners times. The name with the lowest time would be rank1 and so on.

[tatortot02]

This gives me the same output for the names, I need help determining rank 1, rank2, rank3, rank4 and rank5 according to the runners times. The name with the lowest time would be rank1 and so on.

If it were my program, I would create a struct called "Runner" or something along those lines. You could have a string for the runners name included, and then a float for their time. Create a vector of 5 runners. Then, using a sort (for this a bubble sort would suffice) you can reorder the vector in order of which time was the lowest, then the next, then the next, etc. Now, since the runners are completely reordered in the vector, you can use that for loop to output each of their names and times in correct order.

[tejen]

Thanks for the tip. I haven't gotten as far as learning about structs, vectors and sorts ( maybe thats why i'm having such a hard time trying to figure this out). But I will try what you suggested. again, Thank you.