C++ Date and Time

[josefalarka]

I need help please. I am new to C++. I want to create a program that would compute the weekly salary of the employees. The program would accept TIME-IN and TIME-OUT inputs then get the total hours for the day. The time format is in military time (e.g. 13:00 is 1:30 pm). I also want to get the total hours for the week.

Inputs: (1234, Josef Alarka, 380.00, 08:00, 17:01, and June 11-15, 2009)

Employee Number: 12345
Name: Josef Alarka
Salary Rate: 380.00
Time-In for Monday: 08:00
Time-Out for Monday: 17:01
.
.time in, time-out from monday to friday.
.
Time-In for Friday: 08:00
Time-Out for Friday: 17:01
Coverage Date: June 11-15, 2009

Outputs:
************************
Employee Number: 1234
Name: Josef Alarka
Salary Rate: Php 380.00 (with currency format. still i don't know how to format this)
************************
Date Covered: June 11-15, 2009
Total Number of Hours Worked: 40 hrs.
Net Income: Php 1900.00
************************

Any help is very much appreciated. Thank you very much.

[monarch_dodra]

The time format is in military time (e.g. 13:00 is 1:30 pm).

1- You are confusing "Military Time" and "24h date format".
2- 13:00 is NOT 1:30pm. it is 1:00pm. For example, 21:35 is 9h35pm.

anyways, after this short rant, you should know that c++ has no built in time/date classes.
You can either create your own (HIGHLY NOT RECOMMENDED), or look for a third party one. Boost probably has something, but I'm not sure.

[Amleto]

boost has a large date-time lib. it can be a bit difficult to find what you want if its the first time using it.

[ninja9578]

wxWidgets also has a nice date/time library.

Actually, C++ does have a time structure... kind of. It's a C structure, so it's not recommended that you use in in your C++ code, but you can. It's called tm and it's in time.h

[josefalarka]

Still confused how to input the TIME-IN and TIME-OUT. My sample code below;

#include<iostream.h>
#include<time.h>
int main()
{
time_t T_in;
time_t T_out;
time_t T_dif;

cout<<"TIME-IN: ";
cin>>T_in;
cout<<"TIME-OUT: ";
cin>>T_out;

T_dif = T_out - T_in;

cout<<"The total hours worked is: "<<T_dif<<endl;

return 0;
}

OUTPUT:

TIME-IN: 7:30
TIME-OUT: The total hours worked is: -7

I think the only value stored in T_in after I entered 7:30, is just 7. How to resolved this? Please help.

[D_Drmmr]

You have to check the validity of the input. E.g.

if (cin >> T_in) {
    // valid input
}
else {
    // invalid input, need to flush input buffer
}

I'm not sure what the input format for time_t is.