Need help with MySQL...

[7Priest7]

I have never liked MySQL as a storage method...
In the past I have just used Plain Text files to bypass it...
However my current project requires more security...

anyhow here is the problem code...

function search($select,$table,$row,$search,$row2=null,$search2=null){
$x = mysql_connect('localhost','root','root');
mysql_select_db('root_bloodmadness',$x);
if($select == '') {$resource = mysql_query("SELECT * FROM $table WHERE $row=`$search`",$x);}
else if(!isset($row2)){ $resource = mysql_query("SELECT $select FROM $table WHERE $row=`$search`",$x);}
else {$resource = mysql_query("SELECT $select FROM $table WHERE $row=`$search` AND $row2=`$search2`",$x);}
$result=mysql_fetch_row($resource);
mysql_close($x);
unset($x);
if(!isset($result[1])){$result = $result[0];}
return $result;
}

function insert($table,$rows,$values) {
$x = mysql_connect('localhost','root','root');
mysql_select_db('root_bloodmadness',$x);
$result = mysql_query("INSERT INTO $table($rows) VALUES($values)");
mysql_close($x);
unset($x);
return $result;
}

function update($table,$row,$value, $row2,$find) {
$x = mysql_connect('localhost','root','root');
mysql_select_db('root_bloodmadness',$x);
$result = mysql_query("UPDATE $table SET $row=$value WHERE $row2=$find");
mysql_close($x);
unset($x);
return $result;
} 

[Fri Jan 14 08:44:08 2011] [error] [client 127.0.0.1] PHP Warning: mysql_fetch_row() expects parameter 1 to be resource, boolean given in C:\\Users\\Alexander\\Documents\\UniServer\\www\\index.php on line 11, referer: http://localhost/index.php

^ I get this error a lot...

With how many ways I modified the above code I am starting to suspect it may be a problem with the function call(I checked the functions and databases and they should work)...

Thanks in advance for any effort made to assist me...