Iterating through vectors

[@Jkl]

Hi,

I am writing code to access vector elements as, to print first "n" elements of vectors out of its total N elements at a time.

For example, Total vector elements : N= 23
Want to print n elements at time : n =3


Can anyone let me know how this can be explored using vectors?

Thanks!

[MrViggy]

Assuming you mean to print the groups of three on new lines, just iterate over all N elements of the vector, printing a newline character after every three elements have been printed.

Viggy

[ninja9578]

use a vector<T>::iterator to iterate through the vector
Have a counter that gets incremented each time
if your counter modulus n is zero, then add a newline

[vatsa]

If you just want to print first n elements,just iterate from first to 3 using iterator.

regards,
Vatsa

www.objectiveprogramming.com

[Eri523]

use a vector<T>::iterator to iterate through the vector
Have a counter that gets incremented each time

If OP already has the counter anyway, I'd suggest to use that to index the vector. No need for an extra iterator.

[Ejaz]

#include <algorithm>
#include <iostream>
#include <vector>

int main() 
{
	int myints[] = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 };
	std::vector< int > ints( myints , myints + sizeof( myints ) / sizeof( int ) );

	size_t offset = 3;

	if ( offset < ints.size() )
	{
		std::for_each( ints.begin() , ints.begin() + offset , []( int v )
		{
			std::cout << v << std::endl;
		} );
	}
	else
		std::cout << "Out of bound" << std::endl;

	return 0; 
}

[@Jkl]

Thanks all for your comments.

I implemented it by setting counter limit and incremented this counter value while printing each vector element.