How to keep list local to the function call (Recursion) in Python

[atinesh229]

I don't see a list(check) in your code, or any other way that you are making a copy of the list.

What I do see is you adding a check for an empty list, but if you want to do that, I suggest:

def coin_change_count(C, check=None):
    # if not empty list, setup a new check list local to function
    if check is None:
        check = [0, 0, 0, 0]
    # ...

then to call it:

coin_change_count(N)

I can see that the test input is hard coded, I can run the program to obtain the actual output, but what is the expected output?

I tried putting

check = list(check)

at start of the function, But still didn't worked. Here is the expected Output.

>> [[2, 0, 0, 1], [0, 0, 2, 0], [1, 1, 1, 0], [2, 2, 0, 0], [4, 0, 0, 0]]
5